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finlep [7]
3 years ago
9

What is the answer to 1/2÷5/8?

Mathematics
2 answers:
Hoochie [10]3 years ago
8 0

Hi Lurch

1/2 divide by 5/8

1/2÷5/8

1/2*8/5 (multiply numerator together and denominator together )

8/10 ( divide the numerator by 2 and same for the denominator )

4/5

I hope that's help , please if you have question(s) ask !


irina [24]3 years ago
3 0
O.8 as decimal form or 8/10 as fraction form
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Find the value of x. Round the length to the nearest tenth of a unit. <br><br> Please help!
Alex777 [14]

Answer:

take 40 degree as reference angle

using tan rule

tan 40 =p/b

0.83=900/x

0.83x=900

x=900/0.83

x=1084.33

x=1084.3(after rounding off to the nearest tenth)

Step-by-step explanation:

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A dairy farm had 9 pastures and 630 cows. The same number of cows are placed in each pasture. How many cows are in each pasture?
rjkz [21]

Answer:


Step-by-step explanation:

if a dairy farm has 630 cows and the same number of cows are placed in each pasture the total number of cows in each pasture is 630

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3 years ago
The function t(x)=3x+1 determines how many cans of green beans a food truck needs to stock on board, where x is the number of sh
artcher [175]

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Read 2 more answers
Suppose box A contains 4 red and 5 blue poker chips and box B contains 6 red and 3 blue poker chips. Then a poker chip is chosen
sergejj [24]

Answer:

0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Coin chosen from box B is red.

Event B: Blue poker chip transferred.

Probability of choosing a red coin:

7/10 of 4/9(red coin from box A)

6/10 of 5/9(blue coin from box A). So

P(A) = \frac{7}{10}*\frac{4}{9} + \frac{6}{10}*\frac{5}{9} = \frac{28 + 30}{90} = 0.6444

Blue chip transferred, red coin chosen:

6/10 of 5/9. So

P(A \cap B) = \frac{6}{10}*\frac{5}{9} = \frac{30}{90} = 0.3333

What is the probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.3333}{0.6444} = 0.5172

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3 years ago
Please help fast! I have a 10 minutes :(
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Maybe 11x? i dont really know, thats all the info we get

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