26. y= -7/3+ 0 or just y= -7/3
27. y= -10
An imaginary number " i " is the squared root of -1, so whenever you square i it's like squaring a squared root. The squared root would cancel and you would be left with just the number under it, that is, the -1.
i ^ 2 = -1
3, 1, -1, -3, -5
-2 -2 -2 -2
a(n) = a₁ + d(n - 1)
a(n) = 3 - 2(n - 1)
a(n) = 3 - 2(n) + 2(1)
a(n) = 3 - 2n + 2
a(n) = -2n + 3 + 2
a(n) = -2n + 5
a₁₄ = -2(14) + 5
a₁₄ = -28 + 5
a₁₄ = -23
The answer is C.
Answer:
- $8000 at 1%
- $2000 at 10%
Step-by-step explanation:
It often works well to let a variable represent the amount invested at the higher rate. Then an equation can be written relating amounts invested to the total interest earned.
__
<h3>setup</h3>
Let x represent the amount invested at 10%. Then 10000-x is the amount invested at 1%. The total interest earned is ...
0.10x +0.01(10000 -x) = 280
<h3>solution</h3>
Simplifying gives ...
0.09x +100 = 280
0.09x = 180 . . . . . . . subtract 100
x = 2000 . . . . . . divide by 0.09
10000 -x = 8000 . . . . amount invested at 1%
<h3>1.</h3>
$8000 should be invested in the 1% account
<h3>2.</h3>
$2000 should be invested in the 10% account
