18 necklaces in 3 hours
18/3 = 6
6 necklaces in 1 hour
hope this helps
Answer:
(a)
x cubed is
=x^3=x3
5 times the cube of x is
=5x^3=5x3
4 times x is
=4x=4x
the quotient of 4 times x and 3 is
=\frac{4x}{3}=34x
so,
the difference of 5 times the cube of x cubed and the quotient of 4 times x and 3 is
=5x^3-\frac{4x}{3}=5x3−34x ..........Answer
(b)
5 times cube of x is
=5x^3=5x3
5 times cube of x divided by 4 times x is
=\frac{5x^3}{4x}=4x5x3 ..........Answer
(c)
difference of 5 times x cube and 4 is
=5x^3 -4=5x3−4
so,
the quotient of the difference of 5 times x cube and 4 and x is
=\frac{5x^3-4}{x}=x5x3−4 ...........Answer
(d)
difference of 5 times x and 4 is
=5x-4=5x−4
so,
the cube of the difference of 5 times x and 4 is is
=(5x-4)^3=(5x−4)3 ............Answer
Remark
You have given the second best answer. Your answer is |x|<1. You should have open circles at 1 and - 1.
Solution
I have enclosed a graph that is not a number line. You could confine yourself to a number line just by tracing out the blue solution (which is the answer you want)
The red solution is what you did.
The blue solution does not include x = 1 nor does it include x = - 1. The number line would show 1 < x < ∞ and -∞ < x < -1
Answer:
b
Step-by-step explanation:
xhxhdjdhxhdhehrhfhchxhdjeurjr
A * b = 21 and b * c = 39. then b is the common factor of the two numbers.
We need to factor these two numbers to know their equivalent values.
21 factors are 1, 3, 7, 21
39 factors are 1, 3, 13, 39
if b = 3, then a = 7 and c = 13.
To check:
a * b = 21 where 7 * 3 = 21 and b * c = 39 where 3 * 13 = 39
We can then conclude the following:
3 is lesser than 7 which is lesser than 13. where b < a < c
OR 13 is greater than 7 which is greater than 3. where c > a > b
not sure if these answers are included in your choices but i hope this helps.