The sum of the square of a number and five times that number is no more than 46
1 answer:
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Answer:
1) -184
2) 13-3(
)+4
Step-by-step explanation:
For problem number 1, Let's start by substituting all the x's for -3
So the equation will look like
p(-3)=-
+7(-3)-10
Now, lets simplify by solving the exponents
First we'll do which equals -27
Now we'll do which equals 9
So now our equation looks like
p(-3)=4(-27)-5(9)+7(-3)-10
Now, we are going to multiply all these numbers
First 4(-27) which equals -108
Now -5(9) which equals -45
And finally 7(-3) which equals -21
Now our equation looks like
p(-3)= -108-45-21-10
Now we can solve
-108-45-21-10=-184
Answer:
= 3n + 3
Step-by-step explanation:
The sequence is arithmetic with explicit formula
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
From the recursive formula
a₁ = 6 and d = 3 [ the constant being added to A(n - 1) ] , then
= 6 + 3(n - 1) = 6 + 3n - 3 = 3n + 3