Answer:
percentage change from 1960 to 1970 =( 0.11 ÷0.25 ) × 100
= 44 %
Percentage change from 1970 to 1980 =( 0.83 ÷ 0.36) × 100
= 230.55%
percentage change from 1980 to 1990 = ( 0.16 ÷ 1.19) × 100
= 13.44%
percentage change from 1990 to 2000 = (- 0.09 ÷ 1.35) × 100
= -6.667%
Step-by-step explanation:
Item : 1960 1970 1980 1990 2000
gallon: $0.25 $0.36 $1.19 $1.35 $1.26
change : 0.36 - 0.25 = 0.11
percentage change from 1960 to 1970 =( 0.11 ÷0.25 ) × 100
= 44 %
Percentage change from 1970 to 1980 =( 0.83 ÷ 0.36) × 100
= 230.55%
percentage change from 1980 to 1990 = ( 0.16 ÷ 1.19) × 100
= 13.44%
percentage change from 1990 to 2000 = (- 0.09 ÷ 1.35) × 100
= -6.667%
The brake horsepower of an engine that’s being tested is coupled to a dynamometer that has a radius arm of 1.70 feet is letter D. 170.
This is an isosceles triangle. Therefore, at the base we have congruent angles (look at the picture).
We have the equation:
(5x + 13)° + (3x + 7)° = 180°
5x + 13 + 3x + 7 = 180 <em>combine like terms</em>
(5x + 3x) + (13 + 7) = 180
8x + 20 = 180 <em>subtract 20 from both sides</em>
8x = 160 <em>divide both sides by 8</em>
<h3>x = 20</h3>
