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AURORKA [14]
3 years ago
9

Write an equation for a polynomial with all the following features: The Degree is 5. The graph of the Polynomial crosses the ver

tical axis at y = 12. The Polynomial has 4 terms.
Mathematics
1 answer:
dimulka [17.4K]3 years ago
4 0

Answer: f(x) = a*x^5 + b*x^3 + c*x^2 + 12.

Step-by-step explanation:

The degree is 5, so we will have a term like:

a*x^5

it crosses the vertical axis at y = 12, then we will have a constant term equal to 12.

The polynomial has 4 terms, and we already defined two, so we can invent two more, such that the exponent must be between 1 and 4

This polynomial can be something like:

f(x) = a*x^5 + b*x^3 + c*x^2 + 12.

where a, b and c are real numbers.

Has 4 terms, f(0) = 12, then it intersects the y-axis at y = 12, and the maximum exponent is 5, then the degree of f(x) is 5.

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