Answer:
- Decay rate, r = 0.014
- Initial Amount =120,000
- P(10)=104,220
Step-by-step explanation:
The exponential function for growth/decay is given as:
In this problem:
The city's initial population is 120,000 and it decreases by 1.4% per year.
- Since the population decreases, it is a Decay Problem.
- Decay rate, r=1.4% =0.014
- Initial Amount =120,000
Therefore, the function is:
When t=10 years
We are required to find an inequality which best represents the relationship between the number of hours gardening g and the total charge c
The inequality which best represents the relationship between the number of hours gardening g and the total charge c is c ≥ 15 + 12g
At least means greater than or equal to (≥)
fixed charge = $15
charges per hour = $12
Total charge = c
Number of hours = g
The inequality:
<em>Total charge ≥ fixed charge + (charges per hour × Number of hours</em>
c ≥ 15 + (12 × g)
c ≥ 15 + (12g)
c ≥ 15 + 12g
Therefore, the inequality which best represents the relationship between the number of hours gardening g and the total charge c is c ≥ 15 + 12g
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brainly.com/question/11067755
Answer:
Probability of finding girls given that only English students attend the subject =33/59
Step-by-step explanation:
Given that during English lesson, there is no other lesson ongoing. The probability of getting girls in that class only will be equivalent to 33/59 since we expect a total of 59 students out of which 33 will be girls. Similarly, in a Maths class given that only Maths students attend the class, probability of having a girl is 29/61 since out of all students, only 29 prefer Maths and the total class attendance is 61
Let point A(-2,4) = A (X1,Y1)
point B( 1,3 )= B (X2,Y2)
point C(4,-1) = C (X3,Y3)
and point D(?, ?) = D (X4,Y4) We have to find this point
To find X4 we have to use the formula:
X2-X1=X3-X4
Now just plug in the numbers that correspond to the letters provided:
(1)-(-2)=(4)-(X4) ----> we don't know what X4 is yet, so we have to solve for it!
1+2=4-X4
3=4-X4
3-4=-X4
-1=-X4 divide both sides by -1
X4=1
Now we have to find Y4 using this formula:
Y2-Y1=Y3-Y4
Therefore,
(3)-(4)=(-1)-(Y4)
-1=-1-Y4
-1+1=-Y4
0=-Y4
So,
Y4=0
Now we have found the coordinates of the point D, which is (1,0)
Hope this helped!
Q1. The answer is 4(2x - 3)(2x + 1)
16x² – 16x – 12 = 4 * 4x² - 4 * 4x - 4 * 3 =
= 4(4x² - 4x - 3) =
= 4(4x² + 2x - 6x - 3) =
= 4(2x * 2x + 2x - (2x * 3 + 3)) =
= 4(2x(2x + 1) - (3(2x + 1))) =
= 4((2x + 1)(2x - 3)) =
= 4(2x - 3)(2x + 1)
Q2. The answer is 3(x + 8)(x - 1)
3x² + 21x – 24 = 3 * x² + 3 * 7x - 3 * 8 =
= 3(x² + 7x - 8) =
= 3(x *x - x + 8x - 8) =
= 3((x(x - 1) + 8(x - 1)) =
= 3(x + 8)(x - 1)
