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irakobra [83]
3 years ago
7

Translate this sentence into an equation.

Mathematics
1 answer:
Alchen [17]3 years ago
4 0

The answer is <em>j-61=18.</em>

You might be interested in
"759,993 rounded to the nearest hundread
Greeley [361]

Answer:

760,000

Step-by-step explanation:

759,993

we round 993 up to 1,000

6 0
4 years ago
Lisa goes to the mall one day and buys four shirts and three pairs of pants for $85.50. She returns the next day and buys three
hodyreva [135]

Answer:the price for one shirt is $7.5

the price for one pair of pants is $18.5

Step-by-step explanation:

Let x represent the price for one shirt.

Let y represent the price for one pair of pants.

Lisa goes to the mall one day and buys four shirts and three pairs of pants for $85.50. This means that

4x + 3y = 85.5 - - - - - - - - - -1

She returns the next day and buys three shirts and five pairs of pants for $115.00. This means that

3x + 5y = 115 - - - - - - - - - - - 2

Multiplying equation 1 by b3 and equation 2 by 4, it becomes

12x + 9y = 256.5

12x + 20y = 460

Subtracting, it becomes

- 11y = - 203.5

y = - 203.5/ -11 = 18.5

Substituting y = 18.5 into equation 1, it becomes

4x + 3×18.5 = 85.5

4x + 55.5 = 85.5

4x = 85.5 - 55.5 = 30

x = 30/4 = 7.5

4 0
3 years ago
Read 2 more answers
A new car is purchased for 20000 dollars. The value of the car depreciates at 12. 5% per year. What will the value of the car be
Georgia [21]

To solve the problem we need to know about depreciation.

<h2>Formula of Depreciation</h2>

The formula of depreciation is given as,

A = P(1-r)^t

where,

A is the value of an object after t years of time,

P is the value of the object at the beginning, and

r is the rate of depreciation.

The value of the car after 11 years is $4,603.81.

<h2>Explanation</h2>

Given to us

  • Cost of Car at the beginning, p = $20,000
  • Rate of depreciation, r = 12.5%
  • Time, t = 11 years

<h3>Value of the car after 11 years</h3>

Substituting the values in the formula of depreciation,

A = P(1-r)^t

Value of the car after 11 years = P(1-r)^n

                                                 = \$20,000(1-0.125)^{11}\\\\&#10;= \$20,000\times 0.23\\\\&#10;= \$4,603.822 \approx \$4,603.81

Hence, the value of the car after 11 years is $4,603.81.

Learn more about Depreciation:

brainly.com/question/3023490

8 0
3 years ago
Which expression is equivalent to (a^3+b^4+c^5)^2
dalvyx [7]
The answer is a^6b^8c^10
5 0
4 years ago
I NEED ANSWERS RIGHT NOW
Nady [450]

Answer:

The answer is D, $50.09

5 0
3 years ago
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