When the firecracker hits the ground, H(t) = 0.0 = -16t^2 + 90t + 160 Using the quadratic formula,t = (-90 +- sqrt(90^2 - 4(-16)(160))) / 2(-16)t = -1.42 ort = 7.04
The negative time is extraneous. Therefore,t = 7.04 s.
Seven Seconds is your answer!
Answer: 64
Step-by-step explanation:
If EFGH is a parallelogram, its diagonals bisect each other meaning EJ and JG are congruent.
EJ = JG
4w + 4 = 2w + 18
Subtract 2w from both sides
2w + 4 = 18
Subtract 4 from both sides
2w = 14
Divide both sides by 2
w = 7
EG = EJ + JG
EG = 4w + 4 + 2w + 18
EG = 6w + 22
Now that we know what 'w' is, we can substitute it for 7
EG = 6 (7) + 22
EG = 42 + 22 = 64
The measure of EG is 64.
Hope that helped!
Answer:D I think might be wrong
Step-by-step explanation:
