Four $5 bills and two $1 bills
In total it’s six bills
5(4)=20 and 1(2)=2
20+2=22
327421537566 this is just getting repetitive <span />
Answer:
r=7
d=14
Step-by-step explanation:
You need to divide and then you need to you the symbol pie.
Answer:
negative multiples of 3 less than -3
Step-by-step explanation:
if m <9, then
m ={8,7,6,5,4,3,2,1,0,-1,-2,....,..........}
And |6m-55|
So is said that,
when, m= 8
6(8)-55=-6
when, m=7
6(7)-54=-12
when, m = 6
6(6)-54=-18
Since the trend is negative multiples of 3 less than -3
this is my answer
Answer:
0.00665
0.006951
Step-by-step explanation:
If the first child is born with the affliction, there's a 0.05 probability that the second child will be born with the affliction. Which means there's a 0.95 probability that they won't.
The probability that the first child is born with the affliction but not the second is therefore:
P = 0.007 × 0.95
P = 0.00665
There's a 0.007 probability that the first child will be born with the affliction, which means there's a 0.993 probability that they won't. If the first child isn't born with the affliction, then the probability the second child will have it is 0.007.
So the probability that the first child is not born with the affliction and the second child is would be:
P = 0.993 × 0.007
P = 0.006951