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just olya [345]
3 years ago
15

When she just turned 22, Rae purchased 145 shares of Stock A for $25 per share; 87 shares of Stock B for $38 per share; 46 share

s of Stock C for $87 per share; and 115 shares of Stock D for $25 per share. At age 32, Rae sold Stock A for $3740 with annual dividends of $80 per year, Stock B for $3852, Stock C for $3950, and Stock D for $3225. Which stock provided Reese with the greatest return on her investment?
Mathematics
1 answer:
Damm [24]3 years ago
8 0

Answer:

170

Step-by-step explanation:

you have to divide

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I bombed this test plz help.
Eddi Din [679]

Step-by-step explanation:

a = -52 - b / 4

b = -52 - 4a

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5 0
3 years ago
Assume that there is a 4​% rate of disk drive failure in a year. a. If all your computer data is stored on a hard disk drive wit
kap26 [50]

Answer:

a) 99.84% probability that during a​ year, you can avoid catastrophe with at least one working​ drive

b) 99.999744% probability that during a​ year, you can avoid catastrophe with at least one working​ drive

Step-by-step explanation:

For each disk drive, there are only two possible outcomes. Either it works, or it does not. The disks are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

4​% rate of disk drive failure in a year.

This means that 96% work correctly, p = 0.96

a. If all your computer data is stored on a hard disk drive with a copy stored on a second hard disk​ drive, what is the probability that during a​ year, you can avoid catastrophe with at least one working​ drive?

This is P(X \ geq 1) when n = 2

We know that either none of the disks work, or at least one does. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1). So

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{2,0}.(0.96)^{0}.(0.04)^{2} = 0.0016

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0016 = 0.9984

99.84% probability that during a​ year, you can avoid catastrophe with at least one working​ drive

b. If copies of all your computer data are stored on four independent hard disk​ drives, what is the probability that during a​ year, you can avoid catastrophe with at least one working​ drive?

This is P(X \ geq 1) when n = 4

We know that either none of the disks work, or at least one does. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1). So

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{4,0}.(0.96)^{0}.(0.04)^{4} = 0.00000256

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.00000256 = 0.99999744

99.999744% probability that during a​ year, you can avoid catastrophe with at least one working​ drive

7 0
3 years ago
How to solve this question? Adding algebraic fractions
lawyer [7]

Answer:

it should be 2/12 and 9/11

Step-by-step explanation:

5 0
3 years ago
Please help me with number 21. Explain to me how u got the answer
dalvyx [7]
1 meter is 100 centimeters so do 200÷10 what does that leavr you with ? 20
6 0
3 years ago
Read 2 more answers
-6y+15= -27 what is y?
stealth61 [152]

Answer:

y=7

Step-by-step explanation:

-6y= -27-15

-6y= -42

y=7

8 0
2 years ago
Read 2 more answers
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