Answer:
the least common multiple is 18
Step-by-step explanation:
Your answer would be the last option, (6x² - 5)(x² + 2).
This is because when you expand it, you get:
6x² × x² = 6x⁴
6x² × 2 = 12x²
-5 × x² = -5x²
-5 × 2 = -10
Which are all the correct terms.
I hope this helps!
0 - (-6)
<span>-4 - 5
hope they help u out</span>
Answer:
<em><u>6</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>ur</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>help</u></em><em><u> </u></em><em><u>u</u></em><em><u> </u></em>
<em><u>lol</u></em><em><u> </u></em><em><u>:</u></em><em><u>)</u></em>
<em><u>☃️</u></em><em><u>✌</u></em>
<em><u>Merry</u></em><em><u> </u></em><em><u>christmas</u></em><em><u>~</u></em>
Answer:
The stone will be in flight for 3 seconds
Step-by-step explanation:
Given the equation;
d = -16t^2 + vt + h
Where;
v = the initial velocity
h = the initial height
Given;
v = 48 ft/s
h = 0
Substituting into function d;
d = -16t^2 + 48t + 0
d = -16t^2 + 48t
At the point of launch and the point of landing d = 0.
We need to calculate the values of t for d to be equal to zero.
d = -16t^2 + 48t = 0
-16t^2 + 48t = 0
Factorising, we have;
16(-t+3)t = 0
So,
t = 0 or -t+3 = 0
t= 0 or t =3
Change in t is;
∆t = t2 - t1 = 3 - 0
∆t = 3 seconds.
The stone will be in flight for 3 seconds.
