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vovangra [49]
4 years ago
15

2 lawn care companies are competing for a landscaping contract. Company A charges $250. monthly consulting fee plus $10. per squ

are foot of landscaping, While Company B charges a $90. monthly consulting fee plus $12. per square foot of landscaping. Write an equation to represent this. For how many square feet of landscaping will the two companies charge the same amount? How much will the charge be?
Mathematics
2 answers:
kherson [118]4 years ago
3 0
The equations would be

Company A:
250+(10x)

Company B:
90+(12x)

80ft would cost the same. The cost would be 1,050
kirza4 [7]4 years ago
3 0

Answer:

Let x be the no.of square feet for landscaping

Company A

Monthly consulting fee = $250

Cost of landscaping of 1 sq.feet = $10

Cost of landscaping of x sq.feet = $10x

So, Total charge by company A = 250+10x  ---1

Company B

Monthly consulting fee = $90

Cost of landscaping of 1 sq.feet = $12

Cost of landscaping of x sq.feet = $12x

So, Total charge by company B = 90+12x   ---2

Now we are supposed to find  how many square feet of landscaping will the two companies charge the same amount

So, Equate 1 and 2

250+10x=90+12x

160=2x

80=x

So, the two companies charge the same amount for 80 sq.feet

Total charge by company A for 80 sq.feet = 250+10(80)= $1050

Total charge by company B for 80 sq.feet = 90+12(90)=$1170

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Step-by-step explanation:

short hand radius = 4

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distance travellled in 2 day revolution= 25.1+ 25.1 = 50.2

long hand radius= 6

each hour 1 revolution by long hand so in 24 hr 24 revolutions and 48 he 48 revolution

distance travelled in 1 hr = 2πr= 2 x 22/7 x 6= 37.7

distance in 48hr = 37.7 x 48= 1809.6 (approx)

so sum of both= 1809.6 + 50.2 = 1859.8

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3 years ago
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let's take admission fee= z

8z+11z=17.50+21.25

19z=38.75

z=38.25/19

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kondaur [170]
The asnwer is 3u-4

just divide like terms
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The temperature is -3°C. As the day progresses, the temperature increases by 8°C, then drops by 6°C. Find the final temperature.
Volgvan

We know that the initial temperature is -3 then it rises to 8 and drops by 6 degrees then you just need to subtract six from 8                                                         \displaystyle\  8-6=2^\circ \\\\Answer: the\ secondary\ temperature \ will \ be equal \ to  \ 2^\circ

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sergey [27]

a)13

b) skewed

c) IQR

d)Sam's observation is correct

e)6.17

Step-by-step explanation:

Step 1 :

From the histogram we can infer that

0 to 2 texts has been sent by 1 student

2 to 4 texts has been sent by 3 student

4 to 6 texts has been sent by 4 student

6 to 8 texts has been sent by 4 student

8 to 10 texts has been sent by 5 student

Step 2:

a)

From step 1 , we can see that there are total of 17 students represented by the histogram

Step 3:

b)

This is a skewed histogram because we have all large values of students on the right of the histogram and smaller values on the left of the histogram.

In symmetrical histogram, there would be large values on the center and the smaller values on both sides.

Step 4:

c)

IQR would be better recommendation for this as this is a skewed histogram

Standard deviation would be recommended for a symmetrical histogram

Step 5:

d)

Total number of students is 17

Number of students who text between 8 to 10 messages is 5

Hence the students who text between 8 and 10 messages is 5/17

which is nearly 1/3 rd of the total students.

Hence Sam's observation is correct

Step 6:

e)

Mean amount of the texts = (1 * 3 + 3* 3 + 5*4 +7*4 + 9* 5) /17 = 6.17

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3 years ago
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