Answer:
Na₁₁ = 1s² 2s² 2p⁶ 3s¹
Explanation:
Abbreviated and unabbreviated electronic configuration:
The abbreviated electronic configuration uses the noble gas configuration i.e complete electronic shells. For example, the atomic number of neon is ten and sodium is eleven. The abbreviated electronic configuration of sodium is written by using the neon abbreviation in following way:
The electronic configuration of neon is given below:
Ne₁₀ = 1s² 2s² 2p⁶
The abbreviated electronic configuration of sodium:
Na₁₁ = [Ne] 3s¹
While the unabbreviated electronic configuration is written without using noble gas electronic configuration.
Unabbreviated electronic configuration of sodium:
Na₁₁ = 1s² 2s² 2p⁶ 3s¹
<u>Answer:</u> The molarity of stock solution of luminol is 1.055 M
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
Given mass of luminol = 14.0 g
Molar mass of luminol = 177 g/mol
Volume of solution = 75.0 mL
Putting values in above equation, we get:
Hence, the molarity of stock solution of luminol is 1.055 M
There are 20 milligrams in 0.2 decigrams
The lines around the finger of the doorknob represent the electric force on the charged objects.