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4 years ago

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Two angles are suppplementary if their sum is 180. The larger angle measures four degrees more than seven times the measure of a

smaller angle. If x represents the measure of the smaller angle and these two angles are supplementary, find the measure of each angle

1 answer:

olchik [2.2K]4 years ago

4 0

<span>Let the smaller angle be x
The larger angle will be 3x+8
X+3x+8=180

4x=180-8=172
X=172/4
X=43
3*43+8= 137</span>

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3√x -2/x^2<br><br>please show step by step of differentiation before combining the terms.

EastWind [94]

Answer:

Step-by-step explanation:

Before we differentiate, let us assign a variable to the function. Let y be equal to the function i.e let y = 3√x -2/x²

In differentiation if $y = ax^{n}$ , then $\frac{dy}{dx} = nax^{n-1}$ where n is a constant and dy/dx means we are differentiating the function y with respect to x.

Applying the formula o the question given;

$y= 3\sqrt{x} -2/x^2\\y = 3{x}^\frac{1}{2} - 2x^{-2} \\\\$

On differentiating the resulting function;

$\frac{dy}{dx} = \frac{1}{2}*3x^{\frac{1}{2}-1 } - (-2)x^{-2-1} \\\\\frac{dy}{dx} = \frac{1}{2}*3x^{-\frac{1}{2}} + 2x^{-3}\\ \\\frac{dy}{dx} = \frac{1}{2}*{\frac{3}{x^{\frac{1}{2} } }} + \frac{2}{x^{3} } \\\\\frac{dy}{dx} = {\frac{3}{2x^{\frac{1}{2} } }} + \frac{2}{x^{3} }\\\\\frac{dy}{dx} = {\frac{3}{2\sqrt{x} }} + \frac{2}{x^{3} }$

To combine the terms, we will add up by finding their LCM.

$\frac{dy}{dx} = {\frac{3}{2\sqrt{x} }} + \frac{2}{x^{3} }\\\frac{dy}{dx} = \frac{3x^3+4\sqrt{x} }{2x^{3} \sqrt{x}}$

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4 years ago

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Anna11 [10]

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3 years ago

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natta225 [31]

For this case we have to;

We have that an equation in slope-intercept form is given by:

$y = mx + b$

Where:

m is the slope

b is the cut point with the y axis

Also, by definition, two lines are perpendicular when the product of their slopes is -1. That is: $m_ {1} * m_ {2} = - 1$

We have the line as data: $y_ {1} = \frac {-5} {2} x + 6$

Then $m_ {1} = \frac {-5} {2}$

We found $m_ {2}$ :

$m_ {1} * m_ {2} = - 1$

$\frac {-5} {2} * m_ {2} = - 1$

$m_ {2} = \frac {-1} {(\frac {-5} {2})}$

$m_ {2} = \frac {(2) (- 1)} {(- 5) (1)}$

$m_ {2} = \frac {2} {5}$

Thus, $y_ {2} = \frac {2} {5} x_ {2} + b_ {2}$

We must find $b_ {2}$ :

We know that $y_ {2}$ passes through the point $(x_ {2}, y_ {2}) = (5,0)$

We substitute the point in the equation of $y_ {2}$ :

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Thus, $y_ {2} = \frac {2} {5} x_ {2} -2$

Then the equation in slope-intercept for the line that passes through (5,0) and is perpendicular to the line described by $y_ {1} = \frac {-5} {2} x_{1} + 6$ is: $y_ {2} = \frac {2} {5} x_ {2} -2$

Answer:

$y_ {2} = \frac {2} {5} x_ {2} -2$

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3 years ago

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vfiekz [6]

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Nata [24]

Answer:

No.

Step-by-step explanation:

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Therefore, a triangle cannot have these side lengths.

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3 years ago