Answer:
c. 3a^2b^11/2
Step-by-step explanation:
The applicable rule of exponents is ...
(a^b)/(a^c) = a^(b-c)
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Answer:
<h2>
<em><u>-120</u></em></h2>
Step-by-step explanation:
4(-5)(-2)(-3)
= -20 × 6
= <em><u>-120 (Ans)</u></em>
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Answer: the required probability is 0.03516
Step-by-step explanation:
Given the data in the question;
let F represent dominant allele that causes fluffy fur and
f represent corresponding recessive allele that causes wiry fur
here are the possible genotypes and corresponding phenotypes;
FF = Fluffy fur
Ff = Fluffy fur
ff = Wiry fur
genotype of parents is Ff and Ff
and there cross will be; Ff x Ff
now Offspring will be;
F f
F FF Ff
f Ff ff
so the probability that the offspring will have fluffy fur = 3/4
and the probability that the offspring will have wiry fur = 1/4
The probability that the first 2 out of 4 offspring will have fluffy fur will be;
⇒ 3/4 × 3/4 × 1/4 × 1/4 = 0.03516
Therefore, the required probability is 0.03516
