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Aliun [14]
3 years ago
15

Write an equation of a line parallel to y = 5x + 4 that passes through (-1, 2)

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
5 0

Answer:

y=5x+7

Step-by-step explanation:

step 1

Find the slope of the line parallel to the given line

we know that

If two lines are parallel, then their slopes are equal

The equation of the given line is y=5x+4

The slope of the given line is m=5

so

The slope of the line parallel to the given line is also m=5

step 2

Find the equation of the line parallel to the given line

The equation of the line in point slope form is

y-y1=m(x-x1)

we have

m=5

point\ (-1,2)

substitute

y-2=5(x+1)

step 3

Convert to slope intercept form

Isolate the variable y

y-2=5x+5

y=5x+5+2

y=5x+7

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Please help i will mark brainliest
Evgen [1.6K]

Answer:

2. \left[\begin{array}{ccc}1&4\\0&3\\\end{array}\right]

3. \left[\begin{array}{ccc}-3&21&60\\-15&9&-45\\\end{array}\right]

4. \left[\begin{array}{ccc}6&-14\\-2&-6\\\end{array}\right]

Step-by-step explanation:

2. This matrix is easy, as it just requires addition.

\left[\begin{array}{ccc}1&4\\0&3\\\end{array}\right]    +     \left[\begin{array}{ccc}0&0\\0&0\\\end{array}\right]   =  \left[\begin{array}{ccc}1&4\\0&3\\\end{array}\right]

3. This matrix requires for the matrices to be multiplied first, then added.

\left[\begin{array}{ccc}9&-15&18\\-27&15&-9\\\end{array}\right]    +     \left[\begin{array}{ccc}-12&36&42 \\12& -6 & -36 \\\end{array}\right]     =   \left[\begin{array}{ccc}-3&21&60\\-15&9&-45\\\end{array}\right]

4.  Here we can add the last 2 matrices to find x.

\left[\begin{array}{ccc}2&-8\\-4&2\\\end{array}\right]   +   \left[\begin{array}{ccc}4&-6\\2&-8 \\\end{array}\right]  = \left[\begin{array}{ccc}6&-14\\-2&-6\\\end{array}\right]

Hope this helps! (Please consider giving brainliest)

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3 years ago
Using the discriminant determine the number of real solutions -4x^2+20x-25=0
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Step-by-step explanation:

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Pepsi [2]

Answer:

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Step-by-step explanation:


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