Question

Blackbody A peaks at 2000 Å. Blackbody B, which has the same surface area, peaks at 10,000 Å. (a) Which emits more radiation per second at 2,000 Å? (b) Which emits more radiation per second at 10,000 Å? (Textbook, 4th edition, question 3, p. 307, slightly reworded)

Answer 1

Answer:

In both cases the Blackbody A will emit more radiation.

Explanation:

We have to remember that blackbodies that have different peacks but same surface area the one with the smallest peak will always emit more radiation, since the formula goes:

AT=B

Where A is peak and T is total temperature, and B is weins constant.

So if we solve it for A it would look like this:

A=B/T

Meaning that the higher the temperature the lowest the radiation.