Answer:
a
The estimate is 
b
Method B this is because the faulty breaks are less
Step-by-step explanation:
The number of microchips broken in method A is 
The number of faulty breaks of method A is 
The number of microchips broken in method B is 
The number of faulty breaks of method A is 
The proportion of the faulty breaks to the total breaks in method A is


The proportion of the faulty to the total breaks in method B is

For this estimation the standard error is

substituting values


The z-values of confidence coefficient of 0.95 from the z-table is

The difference between proportions of improperly broken microchips for the two breaking methods is mathematically represented as
![K = [p_1 - p_2 ] \pm z_{0.95} * SE](https://tex.z-dn.net/?f=K%20%3D%20%5Bp_1%20-%20p_2%20%5D%20%5Cpm%20z_%7B0.95%7D%20%2A%20SE)
substituting values
![K = [0.08 - 0.07 ] \pm 1.96 *0.0186](https://tex.z-dn.net/?f=K%20%3D%20%5B0.08%20-%200.07%20%5D%20%5Cpm%201.96%20%2A0.0186)

The interval of the difference between proportions of improperly broken microchips for the two breaking methods is

I'm guessing there are 12 lions since half of twelve is 6 and there is only 2 male lions. I would put down 12. Hope that helps!
Daniel spent $4.75 for a lunch and $1.85 for a snack
$4.75+$1.85=$6.6, so Daniel spent $6.6 total
Kyle spent $5.75 for lunch and $1.00 for a snack
$5.75+$1.00=$6.75, so Kyle spend total $6.75.
Final step:
$6.75-$6.6=$0.15. As a result, Kyle spent $0.15 or 15 cent more than Daniel. Hope it help!