Question

a safe has a 4-digit lock code that does not include zero as a digit and no digit is repeated. What is the probability that the lock code consists of all even didgits?

Answer 1

Answer:

               $\dfrac1{126}$

Step-by-step explanation:

9 all possible digits (1, 2, 3, 3, 4, 5, 6, 7, 8, 9)

4 digits and no digits repeated so

9•8•7•6      - number of all possible codes

4 even digits (2, 4, 6, 8)

4 digits and no digits repeated so

4•3•2•1       - number of all codes wich consists of all even digits

What is the probability that the lock code consists of all even didgit:

$\dfrac{4\cdot3\cdot2\cdot1}{9\cdot8\cdot7\cdot6}=\dfrac{1\cdot1\cdot1\cdot1}{9\cdot2\cdot7\cdot1}=\dfrac1{126}$