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4 years ago

-3(y+6)-4(y+3) simplify

Mathematics

2 answers:

Tom [10]4 years ago

7 0

I believe the answer is -7y-30

Paha777 [63]4 years ago

5 0

Answer:

-7y - 30

Step-by-step explanation:

-3y - 18 - 4y - 12

= -7y - 30

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Write the fraction in lowest terms. 13/17

Dmitry [639]

13/17 is at the lowest because they are both prime numbers.

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3 years ago

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1/2(4n-8)+10=4(n+5)

madreJ [45]

Answer:

n= -7

Step-by-step explanation:

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4 years ago

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Find the length of __ JK Round answer to nearest tenth.

PIT_PIT [208]

Answer:

Step-by-step explanation:

We would apply the law of Cosines which is expressed as

a² = b² + c² - 2abCosA

Where a,b and c are the length of each side of the triangle and A is the angle corresponding to a. Likening the expression to the given triangle, it becomes

JK² = JL² + KL² - 2(JL × KL)Cos10

JK² = 61² + 53² - 2(61 × 53)Cos10

JK² = 3721 + 2809 - 6466Cos10

JK² = 6530 - 6367.767

JK² = 162.233

Taking square root of both sides of the equation, it becomes

JK = √162.233

JK = 12.73 to the nearest tenth

6 0

3 years ago

1. Gwen deposits $7,000 in a savings account with an annual interest rate of 2.5%. What function

xeze [42]

Answer:

Results are below.

Step-by-step explanation:

Giving the following information:

Initial investment (PV)= $7,000

Interest rate (i)= 2.5%

To calculate the future value after x years, we need to use the following formula:

FV= PV*(1 + i)^x

Now, for 9 years:

x= 9

FV= 7,000*(1.025^9)

FV=$8,742.04

8 0

3 years ago

Need the a answer for this

FinnZ [79.3K]

Answer:

Given expression:

$\dfrac{14a^4b^6c^{-10}}{8a^{-2}b^3c^{-5}}$

Separate the variables:

$\implies \dfrac{14}{8} \cdot \dfrac{a^4}{a^{-2}} \cdot \dfrac{b^6}{b^3} \cdot \dfrac{c^{-10}}{c^{-5}}$

Reduce the first fraction:

$\implies \dfrac{7}{4} \cdot \dfrac{a^4}{a^{-2}} \cdot \dfrac{b^6}{b^3} \cdot \dfrac{c^{-10}}{c^{-5}}$

$\textsf{Apply Division Property of Exponents rule} \quad \dfrac{a^b}{a^c}=a^{b-c}:$

$\implies \dfrac{7}{4} \cdot a^{4-(-2)} \cdot b^{6-3} \cdot c^{-10-(-5)}$

$\implies \dfrac{7}{4} \cdot a^{6} \cdot b^{3} \cdot c^{-5}$

$\textsf{Apply Negative Property of Exponents rule} \quad a^{-n}=\dfrac{1}{a^n}$

$\implies \dfrac{7}{4} \cdot a^{6} \cdot b^{3} \cdot \dfrac{1}{c^5}$

Therefore:

$\implies \dfrac{7a^6b^3}{4c^5}$

4 0

2 years ago