Answer:
30/50
Step-by-step explanation:
because there is a y distance of 30 and x distance of 50 from point to point.
8 is the answer 8 is the answer 8 is the answer 8 is the answer 8 is the answer 8 is the answer 8 is the answer 8 is the answer <span>8 is the answer</span>
These are two questions and two answers.
Question 1) Which of the following polar equations is equivalent to the parametric equations below?
<span>
x=t²
y=2t</span>
Answer: option <span>A.) r = 4cot(theta)csc(theta)
</span>
Explanation:
1) Polar coordinates ⇒ x = r cosθ and y = r sinθ
2) replace x and y in the parametric equations:
r cosθ = t²
r sinθ = 2t
3) work r sinθ = 2t
r sinθ/2 = t
(r sinθ / 2)² = t²
4) equal both expressions for t²
r cos θ = (r sin θ / 2 )²
5) simplify
r cos θ = r² (sin θ)² / 4
4 = r (sinθ)² / cos θ
r = 4 cosθ / (sinθ)²
r = 4 cot θ csc θ ↔ which is the option A.
Question 2) Which polar equation is equivalent to the parametric equations below?
<span>
x=sin(theta)cos(theta)+cos(theta)
y=sin^2(theta)+sin(theta)</span>
Answer: option B) r = sinθ + 1
Explanation:
1) Polar coordinates ⇒ x = r cosθ, and y = r sinθ
2) replace x and y in the parametric equations:
a) r cosθ = sin(θ)cos(θ)+cos(θ)
<span>
b) r sinθ =sin²(θ)+sin(θ)</span>
3) work both equations
a) r cosθ = sin(θ)cos(θ)+cos(θ) ⇒ r cosθ = cosθ [ sin θ + 1] ⇒ r = sinθ + 1
<span>
b) r sinθ =sin²(θ)+sin(θ) ⇒ r sinθ = sinθ [sinθ + 1] ⇒ r = sinθ + 1
</span><span>
</span><span>
</span>Therefore, the answer is r = sinθ + 1 which is the option B.
Answer:
Part A; Initial dosage is 10 milligrams
Part B:
8.4113 milligrams after 1 hour
5.0057 milligrams after 4 hours.
Step-by-step explanation:
It is given M(h)= 10 
Initial dosage is the 10 milligrams
After 1 hour, plug in h as 1
So, M(1)=10
Simplify the right side
M(1)=10(0.84113)
M(1)= 8.4113 milligrams.
Now, after 4 hours
M(4)=10 
M(4)=10(0.50057)
M(4) =5.0057 milligrams
Answer:
FIRST EXPRESSION:
- If 
, the value of 
is 
- If 
, the value of is 
- If 
, the value of is 
SECOND EXPRESSION:
- If , the value of 
is 
- If , the value of is 
- If , the value of is 
Yes, for any value of "b" the value of the first expression is greater than the value of the second expression.
Step-by-step explanation:
Substitute the given values of "b" into each expression and evaluate.
- For the first expression , you get:
If → 
If → 
If → 
- For the second expression , you get:
If → 
If → 
If → 
You can observe that for any value of "b" the value of the first expression is greater than the value of the second expression.
