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vitfil [10]
3 years ago
14

Mark estimates that the distance from his house to his school is 15.5 mi. The actual distance is 14.5 mi.

Mathematics
2 answers:
denpristay [2]3 years ago
8 0

Answer:

6.9%.

Step-by-step explanation:

From the given information it is clear that

Estimated distance from Mark's house to his school = 15.5 mi

Actual distance = 14.5 mi.

We need to find the percent error in Mark's estimate.

\text{Percent error}=\dfrac{\text{Estimated Distance - Actual Distance}}{\text{Actual Distance}}\times 100

\text{Percent error}=\dfrac{15.5-14.5}{14.5}\times 100

\text{Percent error}=\dfrac{1}{14.5}\times 100

\text{Percent error}=\dfrac{100}{14.5}

\text{Percent error}=6.8965517

Round the percent to the nearest tenth.

\text{Percent error}\approx 6.9

Therefore, the percent error is 6.9%.

lapo4ka [179]3 years ago
7 0
So the error is 1 mile

I ask what % of 15.5 = 1

How you write this;

x/100 *15.5 = 1

15.5x = 100

x = 100/15.5

x = 6.451629 round up 6.45

% error is 6.45 %
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