Answer:
See below
Step-by-step explanation:
The first one IS decay...as 'x' increases the function decreases
the second and third are NOT ...as 'x' increases the value increases
radioactive decay IS decay (obviously)
the one with e^2x is not ....it grows exponentially as x grows
and finally the last one is decay because as x gets larger the value of y gets smaller
Answer:
Step-by-step explanation:
HEYAA!!!!!
OPTION D
To get the additive inverse of a positive number you put a minus in front of it and to get the additive inverse of a negative number, you remove the minus to make it a positive number.
because when u see the equation u can see it is -3-(-6)
which if u solve it the answer is -3+6=3
so the correct option is (D)
HOPE U UNDERSTOOD
Pattie runs at 5 ft/sec
She has got a head start of 15 feet.
So after 1 second, Pattie runs = (5+15) ft
<span>
= 20 </span>
ft
After 2 second Pattie runs = (20+5)ft
= 25 ft
After 3 second Pattie runs = (25+5) ft
= 30 ft
After 4 seconds Pattie runs = (30+5) ft
= 35 ft
After 5 seconds Pattie runs = (35+5) ft
= 40 ft
After 6 seconds Pattie runs = (40+5) ft
= 45 ft
Now Keith runs at 8 ft/sec
After 1 second Keith runs = 8 ft
After 2 second Keith runs = (8+8) ft
= 16 ft
After 3 second Keith runs = (16+8) ft
= 24 ft
After 4 second Keith runs = (24+8) ft
= 32 ft
After 5 second Keith runs = (32+8) ft
= 40 ft
After 6 second Keith runs = (40+8) ft
= 48 ft
So Pattie will stay ahead of Keith upto 4 seconds. In the 5th second Pattie and Keith will be level and in the 6th second Pattie will be overtaken by Keith.
Answer:
y = 4x + b
Step-by-step explanation:
We know that (3, -2) is on this line. So 3 = m(-2)+b.
This leaves us with two variables the slope (m) and the y intercept (b).
But wait a minute, the slope is given to us since it says slope = 4.
Our equation is now, 3 = 4(-2)+b
3 = -8 + b
b = 11.
Our final equation is now y = 4x + b.
(y,x) is a point on this line.
Hope this helped!
JoeLouis2
Divide the stack into halves, if the stacks are equal, they are even. If they aren't, they are odd.
