What is the common denominator of 3/5, 7/8, and 5/6?

According to government data, 20% of employed women have never been married. If 10 employed women are selected at random, what i

Ierofanga [76]

Answer:

a) $P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302$

b) $P(X\leq 2) = P(X=0) + P(X=1) +P(X=2)$

$P(X=0) = (10C0) (0.2)^0 (1-0.2)^{10-0}= 0.107$

$P(X=1) = (10C1) (0.2)^1 (1-0.2)^{10-1}= 0.268$

$P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302$

And replacing we got:

$P(X\leq 2) = 0.107+0.268+0.302=0.678$

c) For this case we want this probability:

$P(X\geq 8) = P(X=8) + P(X=9) +P(X=10)$

But for this case the probability of success is p =1-0.2= 0.8

We can find the individual probabilities and we got:

$P(X=8) = (10C8) (0.8)^8 (1-0.8)^{10-8} =0.302$

$P(X=9) = (10C9) (0.8)^9 (1-0.8)^{10-9} =0.268$

$P(X=10) = (10C10) (0.8)^{10} (1-0.8)^{10-10} =0.107$

And replacing we got:

$P(X \geq 8) = 0.677$

And replacing we got:

$P(X\geq 8)=0.0000779$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

$X \sim Bin (n=10 ,p=0.2)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Solution to the problem

Let X the random variable "number of women that have never been married" , on this case we now that the distribution of the random variable is:

$X \sim Binom(n=10, p=0.2)$

Part a

We want to find this probability:

$P(X=2)$

And using the probability mass function we got:

$P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302$

Part b

For this case we want this probability:

$P(X\leq 2) = P(X=0) + P(X=1) +P(X=2)$

We can find the individual probabilities and we got:

$P(X=0) = (10C0) (0.2)^0 (1-0.2)^{10-0}= 0.107$

$P(X=1) = (10C1) (0.2)^1 (1-0.2)^{10-1}= 0.268$

$P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302$

And replacing we got:

$P(X\leq 2) = 0.107+0.268+0.302=0.678$

Part c

For this case we want this probability:

$P(X\geq 8) = P(X=8) + P(X=9) +P(X=10)$

But for this case the probability of success is p =1-0.2= 0.8

We can find the individual probabilities and we got:

$P(X=8) = (10C8) (0.8)^8 (1-0.8)^{10-8} =0.302$

$P(X=9) = (10C9) (0.8)^9 (1-0.8)^{10-9} =0.268$

$P(X=10) = (10C10) (0.8)^{10} (1-0.8)^{10-10} =0.107$

And replacing we got:

$P(X \geq 8) = 0.677$

3 0

3 years ago

Is -3y = 5x + 4 perpendicular

aivan3 [116]

Answer:

no it is not perpedicular

Step-by-step explanation:

I plugged the equation into a graphing calculator and the line does not appear to be perpendicular

5 0

3 years ago

Read 2 more answers

4. You sketch a right triangle that has a

stich3 [128]

Answer:

√95 cm

Step-by-step explanation:

To solve, you need to use the pythagorean theorem, or a^2 + b^2 = c^2

The hypotenuse is the c and let one leg be b. You can write:

a^2 + 7^2 = 12^2

a^2 + 49 = 144

Now, you need to solve for a:

a^2 = 144 - 49

a^2 = 95

a = √95 cm, or about 9.75cm

3 0

3 years ago

Read 2 more answers

Which expression is equivalent to the expression below? Select all that apply.

katen-ka-za [31]

Answer:

2 and 3

Step-by-step explanation:

To simplify this expression, you will need to use the distributive property.

Multiply -2/5 by 15 = - 6, -2/5 by -20d = 8d, and -2/5 by 5c = -2c.

you can switch these around to get -6 + 8d - 2c and -2c + 8d - 6.

Hope this helps :)

3 0

3 years ago

Employees at Happy Burger must place a special toy in at least 30% of the Burger Buddy kid's meals sold per day. The table shows

irga5000 [103]

On Monday the percentage was approx. 27% so they did not meet the goal
On Tuesday the percentage was approx. 28% so they did not meet the goal
On Wednesday the percentage was approx. 37% so they did meet the goal
On Thursday the percentage was approx. 37% so they did meet the goal
On Friday the percentage was approx. 34% so they did meet the goal

The employees met the goal 3 times within that week :)

6 0

3 years ago