Please, use " ^ " to denote exponentiation: p(t) = t^2 + 5t + 6.
To find the critical points, differentiate p(t) with respect to t, set the result = to 0, and then solve the resulting equation for t:
p '(t) = 2t + 5 = 0
Solving for t: 2t = -5, and so t = -5/2. (-5/2, p(-5/2)) is the critical point. That evaluates to (-5/2, -0.25). This happens to be the vertex of a parabola that opens up.
Answer:
Angle b is 63
Angle f is 59
Step-by-step explanation:
point R ((:
reason being (-5,-6) over the y axis is (5, -6)
Y/3 + 1/4 = 5/12
4y/12 + 3/12 = 5/12
4y/12 = 2/12
4y = 2
/4 /4
y = 1/2
Therefore y = 1/2
15 is the length of the shorter leg
