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Arlecino [84]
3 years ago
5

Please help me find the Area

Mathematics
2 answers:
Dmitry_Shevchenko [17]3 years ago
8 0

Answer:

8 x 17 x 15 = 2040 that's your area

Step-by-step explanation:

good day and be safe

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mars1129 [50]3 years ago
8 0

Answer:

60 units squared

Step-by-step explanation:

The formula for the area of the triangle is: \frac{base*height}{2}

To work this out you would first have to multiply 8 by 15, which gives 120. Then you would divide 120 by 2, Which gives you 60. This is because the formula is the same for the area of a square however the triangle is half of a square that has the same dimensions.

1) Multiply 8 by 15.

8*15=120

2) Divide 120 by 2.

120/2=60^{2}

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If 3 bars of chocolate cost $15.00 ghana cedis how much will 7 bars cost ratio
Rudiy27

Answer:

7 chocolate bars will cost $35

Step-by-step explanation:

if 3 cost $15 then 1 bar would cost 5 dollars and 5x7=35

here is a ratio:

<u>3</u> = <u>7</u>

15 = 35

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3 years ago
The diagram compares the ratio of girls in the chorus to boys in the chorus what is the ratio of girls to boys if there are 40 s
Gala2k [10]
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so if there are 50 students...
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can someone please help and explain to me on how to do this geometry question please?! Thank youuuuu!!! ❤
qaws [65]
There are 13 angles.
We know that m\angle4=112 and m\angle12=105 (11 angles)

1.

m\angle2+m\angle3+m\angle4=180\qquad\qquad\text{linear angles}\\\\m\angle3+m\angle3+m\angle4=180\qquad\qquad m\angle2=m\angle3\\\\2m\angle3+m\angle4=180\\\\2m\angle3+112=180\\\\2m\angle3=180-112\\\\2m\angle3=68\quad|:2\\\\\boxed{m\angle3=34=m\angle2}

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2.

m\angle3+m\angle12+m\angle11=180\qquad\qquad\text{triangle}\\\\34+105+m\angle11=180\\\\139+m\angle11=180\\\\m\angle11=180-139\\\\\boxed{m\angle11=41}

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3.

m\angle12+m\angle13=180\qquad\qquad\text{linear angles}\\\\105+m\angle13=180\\\\m\angle13=180-105\\\\\boxed{m\angle 13=75}

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4.

m\angle1+m\angle2+m\angle13=180\qquad\qquad\text{triangle}\\\\m\angle1+34+75=180\\\\m\angle1+109=180\\\\m\angle1=180-109\\\\\boxed{m\angle1=71}

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5.

m\angle9=m\angle11\qquad\qquad\text{vertical angles}\\\\\boxed{m\angle9=41}

(5 angles)

6.

m\angle10+m\angle11=180\qquad\qquad\text{linear angles}\\\\m\angle10+41=180\\\\m\angle10=180-41\\\\\boxed{m\angle10=139}

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7. a||b\text{ and } c||d so we have a parallelogram.

m\angle4+m\angle5=180\qquad\text{consecutive angles are supplementary}\\\\112+m\angle5=180\\\\m\angle5=180-112\\\\\boxed{m\angle5=68}

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m\angle8=m\angle5\qquad\qquad\text{opposite angels are congruent}\\\\\boxed{m\angle8=68}

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8.

m\angle7+m\angle8+m\angle9=180\qquad\qquad\text{triangle}\\\\m\angle7+68+41=180\\\\m\angle7+109=180\\\\m\angle7=180-109\\\\\boxed{m\angle7=71}

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9.

m\angle1+m\angle5+m\angle6=180\qquad\qquad\text{triangle}\\\\71+68+m\angle6=180\\\\139+m\angle6=180\\\\m\angle6=180-139\\\\\boxed{m\angle6=41}

6 0
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Ira Lisetskai [31]
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I believe that's the answer!
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