Answer:
Step-by-step explanation:
REcall the following definition of induced operation.
Let * be a binary operation over a set S and H a subset of S. If for every a,b elements in H it happens that a*b is also in H, then the binary operation that is obtained by restricting * to H is called the induced operation.
So, according to this definition, we must show that given two matrices of the specific subset, the product is also in the subset.
For this problem, recall this property of the determinant. Given A,B matrices in Mn(R) then det(AB) = det(A)*det(B).
Case SL2(R):
Let A,B matrices in SL2(R). Then, det(A) and det(B) is different from zero. So
.
So AB is also in SL2(R).
Case GL2(R):
Let A,B matrices in GL2(R). Then, det(A)= det(B)=1 is different from zero. So
.
So AB is also in GL2(R).
With these, we have proved that the matrix multiplication over SL2(R) and GL2(R) is an induced operation from the matrix multiplication over M2(R).
Answer:
B
Step-by-step explanation:
For plan A you would pay $60 for at least one visit but for plan B it would be $40 for one visit
Answer:
Standard form: 
Leading coefficient: 1
Step-by-step explanation:
The leading coefficient is 1 because the leading term is 
.
There are 60 players on football team that are not seniors.
Step-by-step explanation:
<u>Method 1:</u>
Given
Total students = 84
Also given that
2 out of 7 are seniors
Which is 2/7
So in order to find the total number of seniors we will multiply the whole number of students to 2/7
So there are 24 seniors on the football team.
Players that are not seniors = 84 - 24 = 60
There are 60 players who are not seniors.
<u>Method 2:</u>
We can divide the total number by 7, to get how many sets of 7 players will be there
= 84/7 = 12
Now,
Multiplying 12 with 2 will give us the number of seniors in football team.
12*2 = 24 seniors
So,
Not seniors =84-24 = 60
Keywords: Percentage, Units
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