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alukav5142 [94]
4 years ago
14

What is the value of y−5x−3for x = 2 and y = -4

Mathematics
1 answer:
steposvetlana [31]4 years ago
6 0
To solve this equation, we need to input the values of the variables and then simplify. Putting in the values of the variables, this equation becomes: 
-4-5(2)-3=
=-4-10-3=
=-17 

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Hello please answer this thanks
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3 years ago
What percentage of data is between the lower quartile and the upper quartile?
11Alexandr11 [23.1K]
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3 years ago
Trigonometry problem​
IgorC [24]

Answer:

The values are x = 0° or x = 60°

Step-by-step explanation:

Given:

\cos x + \frac{1}{\sqrt{3} }\times \sin x = 1

Let it be in the form of

a\cos x + b\sin x = 1 such that

a = 1

b=\frac{1}{\sqrt{3} }

We have

\sqrt{(a^{2}+b^{2} )}=\sqrt{(1^{2}+(\frac{1}{\sqrt{3} }) ^{2} )}\\=\sqrt{\frac{4}{3}}\\=\frac{2}{\sqrt{3} }

Now, Dividing both the side by \frac{2}{\sqrt{3} } we get

\frac{\sqrt{3} }{2}\cos x + \frac{1}{2}\sin x =\frac{\sqrt{3} }{2}\\

We Know

\sin 60 =\frac{\sqrt{3} }{2}\\and\\\cos 60 = \frac{1}{2}

Now by replacing with above values we get

\sin 60\times \cos x + \cos 60\times \sin x = \frac{\sqrt{3} }{2}\\

Also we have formula

\sin A\times \cos B + \cos A\times \sin B = \sin (A+B)

By applying the above Formula we get

\sin (60+x)=\frac{\sqrt{3} }{2}\\

Also ,

\sin (60)=\frac{\sqrt{3} }{2}\\and\\\sin (120)=\frac{\sqrt{3} }{2}

Comparing we get

 60 + x = 60   or  60 + x = 120

∴ x = 0°               ∴ x = 120 - 60 = 60°    

Therefore, the values are x = 0° or x = 60° i.e between 0° to 360°

5 0
3 years ago
An automobile manufacturer claims that its car has a 28.0 miles/gallon (MPG) rating. An independent testing firm has been contra
d1i1m1o1n [39]

Answer:

<em>The calculated value z = 1.3145 < 2.326 at  0.02 level of significance</em>

<em>The null hypothesis is accepted </em>

<em>Hence An automobile manufacturer claims that its car has a 28.0 miles/gallon (MPG) rating.</em>

Step-by-step explanation:

<em><u>Step(i)</u></em>:-

An automobile manufacturer claims that its car has a 28.0 miles/gallon (MPG) rating.

<em>The mean of the Population 'μ' = 28.0miles/gallon</em>

Given data after testing 270 cars, they found a mean MPG of 27.8. Assume the variance is known to be 6.25.

<em>The sample size 'n' = 270 </em>

<em>Mean of the sample 'x⁻' = 27.8</em>

<em>Given Population variance 'σ² = 6.25</em>

<em>The standard deviation of Population 'σ' = √6.25 = 2.5</em>

<u><em>Step(ii):-</em></u>

<em>Null hypothesis :H₀: 'μ' = 28.</em>

<em>Alternative hypothesis :H₁: 'μ' ≠28.</em>

<em>The test statistic </em>

<em></em>Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }<em></em>

<em></em>Z = \frac{27.8-28 }{\frac{2.5}{\sqrt{270} } } = \frac{-0.2}{0.15214}<em></em>

<em>Z = -1.3145</em>

|Z| = |<em>-1.3145|= 1.3145</em>

<u><em>Step(iii)</em></u><em>:-</em>

<em>The tabulated value  of z-score at 0.02 level of significance = 2.326</em>

The calculated value z = 1.3145 < 2.326 at a t 0.02 level of significance

<em>The null hypothesis is accepted </em>

<em>Hence An automobile manufacturer claims that its car has a 28.0 miles/gallon (MPG) rating.</em>

<em></em>

<em></em>

8 0
4 years ago
Which of the following expressions is equivalent to the expression 36 + 42?
olga2289 [7]
The answer is 6(6 + 7)
7 0
3 years ago
Read 2 more answers
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