To solve this problem we need to know the form of the general equation of the line. That is, y= mx+b where m is the slope and b is the intercept. We are already given the y-intercept (2) our next step is to fin the slope. Substitute the point give (1,1) in the equation y= mx+2 and then solve for m. The slope is then -6. The final equation is y = -x+2 or <span>x + y - 2 = 0</span>
Answer:
The answer is 1 & 7/8 or the middle option
Answer:
so ....where is the question?
I'd suggest using "elimination by addition and subtraction" here, altho' there are other approaches (such as matrices, substitution, etc.).
Note that if you add the 3rd equation to the second, the x terms cancel out, and you are left with the system
- y + 3z = -2
y + z = -2
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4z = -4, so z = -1.
Next, multiply the 3rd equation by 2: You'll get -2x + 2y + 2z = -2.
Add this result to the first equation. The 2x terms will cancel, leaving you with the system
2y + 2z = -2
y + z = 4
This would be a good time to subst. -1 for z. We then get:
-2y - 2 = -2. Then y must be 0. y = 0.
Now subst. -1 for z and 0 for y in any of the original equations.
For example, x - (-1) + 3(0) = -2, so x + 1 = -2, or x = -3.
Then a tentative solution is (-3, -1, 0).
It's very important that you ensure that this satisfies all 3 of the originale quations.
