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taurus [48]
3 years ago
13

Wexell Framing's cost formula for its supplies cost is $1,230 per month plus $10 per frame. For the month of October, the compan

y planned for activity of 592 frames, but the actual level of activity was 597 frames. The actual supplies cost for the month was $7,050. The activity variance for supplies cost in October would be closest to:
Business
1 answer:
Gnoma [55]3 years ago
7 0

Answer:

The correct answer is $50 (unfavorable).

Explanation:

According to the scenario, computation of the given data are as follow:-

Planning supply activity cost = (592 × $10) +$1230

= $7,150  

Actual supply activity cost = (597 × $10) + $1230

= $7,200

We can calculate the activity variance for supply cost by using following formula:-

Activity variance for supplies cost = Actual activity cost – Planning activity cost  

= $7,200 - $7,150

= $50  ( positive shows unfavorable)

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Once tradable pollution permits have been allocated to firms:
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Answer: D.

firms that can reduce pollution only at high cost will be willing to pay the most for the pollution permits.

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3 years ago
A plaintiff in a successful lawsuit was awarded a judgment of $4800 per month for 5 years. The plaintiff has the need of a fairl
tatiyna

Answer:

58.81% annual

or 3.93% monthly

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Using a financial calculator, we can determine the internal rate of return of this investment. The initial outlay is -$110,000, and the 60 $4,800 cash flows follow. The IRR is 3.93 per month. In order to determine the effective annual rate, we can use the following formula:

effective annual rate = (1 + 3.93%)¹² - 1 = 58.81%

8 0
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Explain how a manager at a Subway or any fast food restaurant restaurant can use feedforward control to get the best customer sa
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Customer satisfaction is increased as a result of quality management, which also enables businesses to meet customer expectations. One of the key areas where businesses need to be knowledgeable enough is in the service quality.

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Some key features regarding the subway are-

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To know more about the subway, here

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8 0
2 years ago
Raggs, Ltd. a clothing​ firm, determines that in order to sell x​ suits, the price per suit must be p=120 - 0.5 x. It also deter
kodGreya [7K]

Answer:

A) R(x) = 120x - 0.5x^2

B) P(x) = - 0.75x^2 + 120x - 2500

C) 80

D) 2300

E) 80

Explanation:

Given the following :

Price of suit 'x' :

p = 120 - 0.5x

Cost of producing 'x' suits :

C(x)=2500 + 0.25 x^2

A) calculate total revenue 'R(x)'

Total Revenue = price × total quantity sold, If total quantity sold = 'x'

R(x) = (120 - 0.5x) * x

R(x) = 120x - 0.5x^2

B) Total profit, 'p(x)'

Profit = Total revenue - Cost of production

P(x) = R(x) - C(x)

P(x) = (120x - 0.5x^2) - (2500 + 0.25x^2)

P(x) = 120x - 0.5x^2 - 2500 - 0.25x^2

P(x) = - 0.5x^2 - 0.25x^2 + 120x - 2500

P(x) = - 0.75x^2 + 120x - 2500

C) To maximize profit

Find the marginal profit 'p' (x)'

First derivative of p(x)

d/dx (p(x)) = - 2(0.75)x + 120

P'(x) = - 1.5x + 120

-1.5x + 120 = 0

-1.5x = - 120

x = 120 / 1.5

x = 80

D) maximum profit

P(x) = - 0.75x^2 + 120x - 2500

P(80) = - 0.75(80)^2 + 120(80) - 2500

= -0.75(6400) + 9600 - 2500

= -4800 + 9600 - 2500

= 2300

E) price per suit in other to maximize profit

P = 120 - 0.5x

P = 120 - 0.5(80)

P = 120 - 40

P = $80

8 0
3 years ago
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