Answer:
what missing information
Step-by-step explanation:
Answer:
here i finished!
hope it helps yw!
Step-by-step explanation:
The doubling period of a bacterial population is 15 minutes.
At time t = 90 minutes, the bacterial population was 50000.
Round your answers to at least 1 decimal place.
:
We can use the formula:
A = Ao*2^(t/d); where:
A = amt after t time
Ao = initial amt (t=0)
t = time period in question
d = doubling time of substance
In our problem
d = 15 min
t = 90 min
A = 50000
What was the initial population at time t = 0
Ao * 2^(90/15) = 50000
Ao * 2^6 = 50000
We know 2^6 = 64
64(Ao) = 50000
Ao = 50000/64
Ao = 781.25 is the initial population
:
Find the size of the bacterial population after 4 hours
Change 4 hr to 240 min
A = 781.25 * 2^(240/15
A = 781.25 * 2^16
A= 781.25 * 65536
A = 51,199,218.75 after 4 hrs
Answer:
Step-by-step explanation:
We are given that The monthly charge for a waste collection service is 1830 dollars for 100 kg of waste
So,
We are also given that The monthly charge for a waste collection service is 2460 dollars for 135 kg of waste.
So,
We are supposed to find a linear model for the cost, C, of waste collection as a function of the number of kilograms, w.
So, we will use two point slope form :
Formula :
Substitute the values
y denotes the cost
x denotes the weight
So, Replace y with C and x with w
So, a linear model for the cost, C, of waste collection as a function of the number of kilograms, w is
Answer:
159
Step-by-step explanation:
k (9) = (2 * ) - 3
= (2 * 81) - 3
= 162 - 3
= 159
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