452 because you will multiply 80 by 6 and get 480 and subtract 28 from that!
26 good luck n I hope you pass
Answer:
23
Step-by-step explanation:
From the graph, derive the best fit equation :
Using the points ;
(0,2.5) (100 ,35)
x1 = 0 ; y1 = 2.5 ; x2 = 100 ; y2 = 35
Slope formula, m = (y2-y1)/(x2-x1)
m = (35-2.5)/(100-0)
m= (32.5)/100
m = 0.325
The y intercept, value on the graph where best fit line crosses the y axis = 2.5
The equation :
y = mx + c
c = intercept ; m = slope
y = 0.325x + 2.5
y = Number of cars
x = number of customers
The number of customers if there are 10 cars parked :
10 = 0.325x + 2.5
10 - 2.5 = 0.325x
7.5 = 0.325x
x = 7.5 / 0.325
x = 23.076
x = 23
First we need slope


Put D co-ordinates on y=mx+b




Now
slope intercept form.

Answer:
t≈8.0927
Step-by-step explanation:
h(t) = -16t^2 + 128t +12
We want to find when h(t) is zero ( or when it hits the ground)
0 = -16t^2 + 128t +12
Completing the square
Subtract 12 from each side
-12 = -16t^2 + 128t
Divide each side by -16
-12/-16 = -16/-16t^2 + 128/-16t
3/4 = t^2 -8t
Take the coefficient of t and divide it by 8
-8/2 = -4
Then square it
(-4) ^2 = 16
Add 16 to each side
16+3/4 = t^2 -8t+16
64/4 + 3/4= (t-4)^2
67/4 = (t-4)^2
Take the square root of each side
±sqrt(67/4) =sqrt( (t-4)^2)
±1/2sqrt(67) = (t-4)
Add 4 to each side
4 ±1/2sqrt(67) = t
The approximate values for t are
t≈-0.092676
t≈8.0927
The first is before the rocket is launched so the only valid answer is the second one