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liraira [26]
3 years ago
14

Give the equation of the circle centered at the origin and passing through the point (0,-8)

Mathematics
1 answer:
Norma-Jean [14]3 years ago
5 0

Answer:

The answer to your question is x ² + y² = 64

Step-by-step explanation:

Process

1.- Find the length of the radius

C (0, 0)

P (0, -8)

d = \sqrt{(x2 - x1)^{2}+ (y2 - y1)^{2}  }

d = \sqrt{(0- 0)^{2}+ (-8 - 0)^{2}  }

d = \sqrt{64}

d = 8

2.- Find the equation of the circle

    (x - h)^{2} + (y - k)^{2} = r^{2} \\

h = 0   and k = 0

    (x - 0)^{2} + (y - 0)^{2} = 8^{2}

            x² + y² = 64      

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