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Vladimir [108]
3 years ago
9

Use the following graph of two theoretical populations (species A and B) to answer the following questions:

Biology
1 answer:
avanturin [10]3 years ago
8 0
A) This is predator-prey relationship.

B) Species A is prey and species B is predator.
- If prey population decreases in number, the predator population will also decrease because there is not enough food for predators to survive and vice versa.

- If predator population decreases, the prey population will increase because less prey will be eaten by predators and vice versa.


C) Let population A be Zebras, and population B Lions.

From the graph, at the beginning the there is increase in Lions, as well as in smaller rate in Zebras. At one point, the population of Lions begins to decrease, so they will eat less Zebras. This will allow Zebras to increase population. With more Zebras on the menu, more Lions will eat and increase their chance to survive. This leads to decrease in Zebra population. But again, with less Zebras, the Lion population must decrease allowing Zebra population to increase, and so on.

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How are photosynthesis and cellular respiration related?
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I'd go with the third one because the products of both of them are oxygen and carbon dioxide.

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3 years ago
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In chickens, comb shape is determined by alleles at two loci (R, r and P, p). A walnut comb is produced when at least one domina
frutty [35]

Answer:

a) All Walnut , Genotype - RrPp

b) Walnut : Rose: Single

1:1:2

Explanation:

Phenotype and their Genotype -

Walnut comb - R_ P_

Rose Comb - R_ pp

Pea Comb - rr P_

Single Comb  - rr pp

a) RR PP *  rr pp

All progenies will have genotype RrPp (Walnut Comb)

b) Rr Pp *  rr pp

RrPp (4), Rrpp (4), rrpp (8)

Walnut : Rose: Single

1:1:2

4 0
3 years ago
The lining of a tubular structure is referred to as the ____ .
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7 0
3 years ago
In which order are the steps of the scientific method commonly listed
Galina-37 [17]
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7 0
3 years ago
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Two mice breed. The male is heterozygous for the dominant traits of black fur and active behavior but is homozygous recessive fo
olya-2409 [2.1K]

Answer:

Four

Explanation:

Let the allele for black fur be B (the alternate will be b), the allele for active behavior be A (the alternate will be a), and the allele for light eyes be L (the alternate will be l).

<em>Heterozygous dominant for black fur = Bb</em>

<em>Heterozygous dominant for active behavior = Aa</em>

<em>Homozygous recessive for light eyes = ll</em>

Hence, the genotype for a male that is heterozygous for the dominant traits of black fur and active behavior but is homozygous recessive for light eyes will be BbAall.

Bb   Aa   ll

Possible Gametes

<em>BAl, Bal, bAl, and bal</em>

Therefore, the number of different types of gametes produced by the male mouse is four.

5 0
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