Question

I need someone to tell me Is my answer right or wrong

Answer 1

3x + y = 6
y = -3x + 6

the line perpendicular to that would be
y = 1/3x + 6

so your slope is 1/3
and your point is (-6, -1)

for this, you would you point slope form to solve
y + 1 = 1/3(x + 6)
y + 1 = 1/3x + 2
y = 1/3x + 1

answer is C

Answer 2

Perpendicular to 3x + y = 6, passes through (-6, -1)

Find the slope.

3x + y = 6

Turn into slope-intercept form by subtracting 3x from both sides.

y = -3x + 6

Our slope is -3.

However, because it is perpendicular to a line, we must find the negative reciprocal. The negative reciprocal is the number turned upside down and then given or taking away a negative. EX : 5/9 turns into -9/5

So, our new slope is 1/3.

Slope₁ = -3

Slope₂ = 1/3

y-y₁=m(x-x₁)

Plug everything in.

{Use the slope 1/3 and the points (-6, -1)}

y - (-1) = 1/3(x - (-6)

Simplify.

y + 1 = 1/3(x + 6)

Simplify.

y + 1 = 1/3x + 2

Subtract 1 from both sides.

y = 1/3x + 1

So, our answer is the THIRD answer choice.

~Hope I helped!~