You can locate<span> any </span>point on the coordinate plane<span> using an ordered pair of numbers.
e.i. (4,2) will be 4 units to the right and 2 units up on the coordinate plane.</span>
Answer:
Answer:
b. -75x+57=-75x+57
Step-by-step explanation:
If an equation after solving does not give the solution but give a true statement then the equation has infinitely many solution,
In option a.
57x+57=-75x-75
57x + 75x = -75 - 57
132x = -132
⇒ x = -1
i.e. it has only one solution,
In option b.
-75x+57=-75x+57
-75x + 75x = 57 - 57
0 = 0 ( True )
i.e. it has infinitely many solution.
In option c.
75x+57=-75x+57
75x + 75x = 57 - 57
150x = 0
⇒ x = 0
i.e. it has only one solution,
In option d.
-57x+57=-75x+75
-57x + 75x = 75 - 57
18x = 18
⇒ x = 1
i.e. it has only one solution.
Step-by-step explanation:
Answer:
question is 2x^2+5x^2-5X^3 if the value of x=2 then we put the value of x in equation= 2(2)^2+5(2)^2-5(2)^3 =2*4+5*4-5*8 = 8+20-40 =28-40 =-12 ans
Let the distance traveled by car X be x km
<span>let the distance traveled by car Y by y km </span>
<span>their paths form a right-angled triangle. </span>
<span>Let the distance between them be D km </span>
<span>D^2 = x^2 + y^2 </span>
<span>2D dD/dt = 2x dx/dt + 2y dy/dt </span>
<span>dD/dt = (x dx/dt + y dy/dt)/D </span>
<span>at the given case: </span>
<span>x = 60, y = 80 , dx/dt = 80, dy/dt = 100 </span>
<span>D^2 = 60^2 + 80^2 = 10000 </span>
<span>D = 100 </span>
<span>dD/dt = (60(80) + 80(100))/100 </span>
<span>= 128 </span>
Answer:
Step-by-step explanation:
Given:
Focus point = (-5, -4)
Vertex point = (-5, -3)
We need to find the equation for the parabola.
Solution:
Since the x-coordinates of the vertex and focus are the same,
so this is a regular vertical parabola, where the x part is squared. Since the vertex is above the focus, this is a right-side down parabola and p is negative.
The vertex of this parabola is at (h, k) and the focus is at (h, k + p). So, directrix is y = k - p.
Substitute y = -4 and k = -3.
So the standard form of the parabola is written as.
Substitute vertex (h, k) = (-5, -3) and p = -1 in the above standard form of the parabola.
So the standard form of the parabola is written as.
Therefore, equation for the parabola with focus at (-5,-4) and vertex at (-5,-3)
