Ask question

Ask question

All categories

4 years ago

10

Write the expression below as a product of two factors (H+6) +(h+6)+(h+6)

1 answer:

lara31 [8.8K]4 years ago

7 0

If you simplify this problem out, it should equal out to be,simplified, 3h+18.
Factored 3(h+6). And it's not a perfect square. (Random)

You might be interested in

Rahul earns 21,000 in 7 months.

tekilochka [14]

Answer:

a _ 12×21000/7 = 36000

b _ 33 × 7 / 21000= 11 months

8 0

3 years ago

Bob and Jimmy went to the gym to lift weights. Jimmy lifted twice as much as Bob. Together they lifted 51lbs. How much did each

Darina [25.2K]

I broke it all the way day half of 51 is 25 in a half and half of 25 is 12 in half so if Jimmy lifted twice as much he may have lifted 25 in a half and bob left 12

8 0

3 years ago

Read 2 more answers

Write the linearization of the function at the points indicated. (Enter your answer as an equation. Let x be the independent var

Natalija [7]

Answer:

$\displaystyle y=5+\frac{x}{10}$

$\displaystyle y=10+\frac{(x-75)}{20}$

Step-by-step explanation:

<u>Linearization</u>

It consists of finding an approximately linear function that behaves as close as possible to the original function near a specific point.

Let y=f(x) a real function and (a,f(a)) the point near which we want to find a linear approximation of f. If f'(x) exists in x=a, then the equation for the linearization of f is

$y=f(x)=f(a)+f'(a)(x-a)$

Let's find the linearization for the function

$y=\sqrt{25+x}$

at (0,5) and (75,10)

Computing f'(x)

$\displaystyle f'(x)=\frac{1}{2\sqrt{25+x}}$

At x=0:

$\displaystyle f'(0)=\frac{1}{2\sqrt{25+0}}=\frac{1}{10}$

We find f(0)

$f(0)=\sqrt{25+0}=5$

Thus the linearization is

$\displaystyle y=f(0)+f'(0)(x-0)=5+\frac{1}{10}x$

$\displaystyle y=5+\frac{x}{10}$

Now at x=75:

$\displaystyle f'(75)=\frac{1}{2\sqrt{25+75}}=\frac{1}{20}$

We find f(75)

$f(75)=\sqrt{25+75}=10$

Thus the linearization is

$\displaystyle y=f(75)+f'(75)(x-75)=10+\frac{1}{20}(x-75)$

$\displaystyle y=10+\frac{(x-75)}{20}$

5 0

3 years ago

An observer (O) spots a bird flying at a 35° angle from a line drawn horizontal to its nest. If the distance from the observer (

romanna [79]

Answer:

The correct option is;

17,202 feet

Step-by-step explanation:

The distance from the observer to the bird is given as 21,000 ft

The angle between the line of flight of the bird to the horizontal line from its nest = 35°

With the triangle BNO = A right triangle, we have;

The distance of the bird from its nest = Adjacent leg of the right triangle

The distance of the observer from the bird = Hypotenuse length

Which by trigonometric relations gives;

$cos(35 ^{\circ} )= \dfrac{Adjacent\ leg \ length}{Hypotenuse \ length} = \dfrac{Distance\ of \ bird \ from \ its \ nest}{21,000}$

21,000×cos(35 degrees) = The distance of the bird from its nest = 17,202.2 feet ≈ 17,202 feet.

6 0

4 years ago

Look at the triangle ABC.

CaHeK987 [17]

Answer:

ahh pythagoras' theorem, my old nemesis...

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers