<h2>
Hello!</h2>
The answer is:
Samir picks
of peppers in the evening.
<h2>
Why?</h2>
To solve this problem, we must remember the way to add or subtract mixed numbers.
We must remember the way of adding or subtracting fractions:
![\frac{a}{b}+\frac{c}{d} =\frac{ad+bc}{bd}](https://tex.z-dn.net/?f=%5Cfrac%7Ba%7D%7Bb%7D%2B%5Cfrac%7Bc%7D%7Bd%7D%20%3D%5Cfrac%7Bad%2Bbc%7D%7Bbd%7D)
Also, if we need to add or subtract mixed numbers with different denominators, we need to follow the next steps:
- Add or subtract the whole number part
- Add or subtract the fractional numbers.
- Put together both, whole number addition or subtraction result and the addition or subtraction of the fractional numbers.
So,
![a\frac{b}{c}+d\frac{e}{f} =(a+d)\frac{bf+ce}{cf}](https://tex.z-dn.net/?f=a%5Cfrac%7Bb%7D%7Bc%7D%2Bd%5Cfrac%7Be%7D%7Bf%7D%20%3D%28a%2Bd%29%5Cfrac%7Bbf%2Bce%7D%7Bcf%7D)
Now, if Samir picks 3 5/8 less peppers in the afternoon than in the evenning, and if he picks 4 3/6 peppers in the afternoon, so:
Let be x the number of peppers that he picks in the evening, so:
![x-3\frac{5}{8}x=4\frac{3}{6}\\\\x=4\frac{3}{6}+3\frac{5}{8}](https://tex.z-dn.net/?f=x-3%5Cfrac%7B5%7D%7B8%7Dx%3D4%5Cfrac%7B3%7D%7B6%7D%5C%5C%5C%5Cx%3D4%5Cfrac%7B3%7D%7B6%7D%2B3%5Cfrac%7B5%7D%7B8%7D)
Then, simplifying we have:
![x=4\frac{3}{6}+3\frac{5}{8}\\\\x=4\frac{3}{6}+3\frac{5}{8}=(4+3)\frac{24+30}{48}\\\\x=(4+3)\frac{24+30}{48}=7\frac{54}{48}=7\frac{9}{8}](https://tex.z-dn.net/?f=x%3D4%5Cfrac%7B3%7D%7B6%7D%2B3%5Cfrac%7B5%7D%7B8%7D%5C%5C%5C%5Cx%3D4%5Cfrac%7B3%7D%7B6%7D%2B3%5Cfrac%7B5%7D%7B8%7D%3D%284%2B3%29%5Cfrac%7B24%2B30%7D%7B48%7D%5C%5C%5C%5Cx%3D%284%2B3%29%5Cfrac%7B24%2B30%7D%7B48%7D%3D7%5Cfrac%7B54%7D%7B48%7D%3D7%5Cfrac%7B9%7D%7B8%7D)
So, Samir picks
of peppers in the evening.
Have a nice day!