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belka [17]
3 years ago
9

A set of cards includes 20 yellow cards, and 24 blue cards. What is the probability, written in decimal form, that a blue card i

s chosen at random? (Help please)
Mathematics
2 answers:
Papessa [141]3 years ago
5 0
.54 I believe. 
20 yellow and 24 blue = 44 cards in all
divide 24 by 44 and you get a .54 repeating decimal. 
sladkih [1.3K]3 years ago
3 0
0.55 
Number of favorable outcome/Total number of possible outcome
24/(20+24)

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The lifetime of a certain type of battery is normally distributed with mean value 11 hours and standard deviation 1 hour. There
tankabanditka [31]

Answer:

The lifetime value needed is 11.8225 hours.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that:

The lifetime of a certain type of battery is normally distributed with mean value 11 hours and standard deviation 1 hour. This means that \mu = 11, \sigma = 1.

What lifetime value is such that the total lifetime of all batteries in a package exceeds that value for only 5% of all packages?

This is the value of THE MEAN SAMPLE X when Z has a pvalue of 0.95. That is between Z = 1.64 and Z = 1.65. So we use Z = 1.645

Since we need the mean sample, we need to find the standard deviation of the sample, that is:

s = \frac{\sigma}{\sqrt{4}} = 0.5

So:

Z = \frac{X - \mu}{s}

1.645 = \frac{X - 11}{0.5}

X - 11 = 0.5*1.645

X = 11.8225

The lifetime value needed is 11.8225 hours.

3 0
3 years ago
45 points! Please help!
Tju [1.3M]

Answer:

Sequence One

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S = a₁ / (1 − r) is the infinite sum of a geometric series where |r| < 1.

Sequence One: r = 1/5

Sequence Two: r = 2

Sequence Three: not geometric

Sequence Four: r = -3/2

Only Sequence One has |r| < 1.

5 0
3 years ago
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Vadim26 [7]

Answer:

its the last one

Step-by-step explanation:

first two are opinion and are not formal, and the third one is off topic

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