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3 years ago

12

Please zoom in before you start solving because there are tricks in here. What is the answer?Please actually look at the picture

closely

2 answers:

patriot [66]3 years ago

7 0

Answer:

109

Step-by-step explanation:

4+15×7 = 109

_____________________

Annette [7]3 years ago

5 0

Answer:

I think 109 is the answer

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In Exercise, expand the logarithmic expression.<br> ln x(x + 1)

34kurt

Answer:

dy/dx = 2x+1/x(x+1)

Step-by-step explanation:

y = In x(x+1)

Let u = x(x+1) = x^2 + x

du/dx = 2x + 1

y = In u

dy/du = 1/u

dy/dx = dy/du × du/dx = 1/u × 2x+1 = 2x+1/u = 2x+1/x(x+1)

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3 years ago

What is the measure of FEG?

MArishka [77]

Answer:

C. 50 degrees

Step-by-step explanation:

Because 6x + 5x = 110° and x = 10

5×10 = FEG 50°

8 0

3 years ago

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tankabanditka [31]

Answer:

b

Step-by-step explanation:

because logic sence

6 0

3 years ago

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9+15÷3(2)-6<br> Please help me

Firlakuza [10]

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Step-by-step explanation:

4 0

3 years ago

Given sin theta= 6/11 and sec theta < 0, find cos theta and tan theta.

bekas [8.4K]

Answer: option a.

Step-by-step explanation:

By definition, we know that:

$cos^2(\theta)=1-sen^2(\theta)\\\\tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

Substitute $sin(\theta)=\frac{6}{11}$ into the first equation, solve for the cosine and simplify. Then, you obtain:

$cos(\theta)=\±\sqrt{1-(\frac{6}{11})^2}\\\\cos(\theta)=\±\sqrt{\frac{85}{121}}\\\\ cos(\theta)=\±\frac{\sqrt{85}}{11}$

As $sec\theta$ then $cos\theta$ :

$cos(\theta)=-\frac{\sqrt{85}}{11}$

Now we can find $tan\theta$ :

$tan\theta=\frac{\frac{6}{11}}{-\frac{\sqrt{85}}{11}}\\\\tan\theta=-\frac{6\sqrt{85}}{85}$

4 0

3 years ago

Read 2 more answers