Ask question

Ask question

All categories

3 years ago

12

Please zoom in before you start solving because there are tricks in here. What is the answer?Please actually look at the picture

closely

2 answers:

patriot [66]3 years ago

7 0

Answer:

109

Step-by-step explanation:

4+15×7 = 109

_____________________

Annette [7]3 years ago

5 0

Answer:

I think 109 is the answer

You might be interested in

PROVE :<br><br>sin^2(-300°).cos^2 (120)+ cos^2(-240 ).sin^2(390)=1/4

leva [86]

Step-by-step explanation:

$\sin {}^{2} ( - 300) \cos {}^{2} (120) + \cos {}^{2} ( - 240) \sin {}^{2} (390) = \frac{1}{4}$

$\sin {}^{2} (60) \cos {}^{2} ( {}^{} 120) + \cos {}^{2} (120) \sin {}^{2} (30)$

$\frac{3}{4} \frac{1}{4} + \frac{1}{4} \frac{1}{4}$

$\frac{3}{16} + \frac{1}{16} = \frac{4}{16} = \frac{1}{4}$

3 0

1 year ago

The residents of a city voted on whether to raise property taxes. The ratio of yes to no was 4 to 3. If there were 4886 total vo

Natalija [7]

Sri but I hope u get the answer right and have a great weekend

7 0

2 years ago

Can someone just explain to me how to do this please

Dmitrij [34]

Answer: -7.5

Step-by-step explanation:

area = 1/2bh.

area = 1/2(x+6)(5)

area = x/2 + 15

area = x/2 = -15

area = x = -7.5

area = -7.5

5 0

2 years ago

Show that d^2y/dx^2=-2x/y^5, if x^3 + y^3=1

aalyn [17]

Answer:

y³ + x³ = 1

First, differentiate the first time, term by term:

${3y^{2}.\frac{dy}{dx} + 3x^{2}} = 0 \\\\{3y^{2}.\frac{dy}{dx} = -3x^{2}} \\\\\frac{dy}{dx} = \frac{-3x^{2}}{3y^{2}} \\\\\frac{dy}{dx} = \frac{-x^{2}}{y^{2}}$

↑ we'll substitute this later (4th step onwards)

Differentiate the second time:

$3y^{2}.\frac{dy}{dx} + 3x^{2} = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} + 6x = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{-x^{2} }{y^{2} })^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{x^{4} }{y^{4} }) = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + \frac{6x^{4} }{y^{3} } = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} = - 6x - \frac{6x^{4} }{y^{3} } \\\\$

$3y^{2}.\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{3y^{2}. y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 2xy^{3} - 2x^{4} }{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (y^{3} + x^{3})}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (1)}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x}{y^{5}}$

3 0

2 years ago

Pick a sport would you rather be on the best team but the worst player or the worst team but you are the best player? why?

Vlada [557]

Answer:

Football. Best player on the worst team.

Step-by-step explanation:

Might as well get that money if the rest of your team sucks.

8 0

2 years ago

Read 2 more answers