3 years ago

Please do me a favor and solve this

Mathematics

1 answer:

Rina8888 [55]3 years ago

4 0

Answer:

negative 3 an lesser, or positive 4 and greater

Step-by-step explanation:

(0^2=0)-0-12 is not greater than or equal to zero

However, everything equal to or lesser than -3 is equal or greater than zero.

(-3^2=9)-(-3)-12=0

(-4^2=16)-(-4)-12=8

and so on

everything greater than or equal to 4 is greater than or equal to 0 as well

(4^2=16)-4-12=0

(5^2=25)-5-12=8

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