My solution to the problem is as follows:
EC = 15 ... draw CF = 6 (radius) ...use Pythagorean theorem to find EF.
EF^2 + CF^2 = EC^2
EF^2 = 15^2 - 6^2 = 189 .... EF = sq root 189
triangle GDE is similar to CFE ... thus proportional
GD / ED = CF / EF
GD / 18 = 6 / (sq root 189)
<span>GD = 108 / (sq root 189)
I hope my answer has come to your help. God bless and have a nice day ahead!
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5.104+4.103+7.10+1=
9.207+7.10+1=
16.307+1=
17.307
Answer:
w =< 70
(width is less or equal to 70 inches)
Step-by-step explanation:
Let l = length, w = width, h = height
Restrictions given in this question:
'sum of perimeter of the base and the height cannot exceed 130 inches'
perimeter of the base is 2 width and 2 length of the box
perimeter = 2w + 2l
Therefore, inequality involves here is
2w + 2l + h =< 130
(Note that =< here means less or equal)
Then a new condition given with
height, h = 60 in
and length is 2.5 times the width
l = 2.5w
Substitute this new condition into the equation will give us the following:
2w + 2(2.5w) + 60 =< 130
2w + 5w + 60 =< 130
7w + 60 =< 130
7w =< 130-60
7w =< 70
w =< 10
Answer:
Step-by-step explanation:
6-3x=12-6x
Only one solution of x=2
