All categories

4 years ago

What is the solution to the inequality below ?

Mathematics

1 answer:

Vlad1618 [11]4 years ago

8 0

[tex]Domain:x\geq0\\\\\sqrt{x}\leq5\ \ \ \ |square\ both\ sides\\\\x\leq25[tex]

Answer: B. 0 ≤ x ≤ 25

You might be interested in

84 km / h in m / s plz help me<br>

PilotLPTM [1.2K]

Answer:

23 $\frac{1}{3}$ m/s

Step-by-step explanation:

We can change the km to m first. 1km = 1000m.

84km/h = 84 000m/h

Then, we can change the h to s. 1h = 3600s.

84 000m/h = 23 $\frac{1}{3}$ m/s

7 0

3 years ago

The first day of a water polo tournament the total value of tickets sold was $17,610. One-day passes sold for $20 and tournament

Alenkasestr [34]

Answer:

gfggfgkfmf

Step-by-step explanation:

3 0

3 years ago

lilavasa [31]

The count of the equilateral triangle is an illustration of areas

There are 150 small equilateral triangles in the regular hexagon

<h3>How to determine the number of equilateral triangle </h3>

The side length of the hexagon is given as:

L = 5

The area of the hexagon is calculated as:

$A = \frac{3\sqrt 3}{2}L^2$

This gives

$A = \frac{3\sqrt 3}{2}* 5^2$

$A = \frac{75\sqrt 3}{2}$

The side length of the equilateral triangle is

l = 1

The area of the triangle is calculated as:

$a = \frac{\sqrt 3}{4}l^2$

So, we have:

$a = \frac{\sqrt 3}{4}*1^2$

$a = \frac{\sqrt 3}{4}$

The number of equilateral triangles in the regular hexagon is then calculated as:

$n = \frac Aa$

This gives

$n = \frac{75\sqrt 3}{2} \div \frac{\sqrt 3}4$

So, we have:

$n = \frac{75}{2} \div \frac{1}4$

Rewrite as:

$n = \frac{75}{2} *\frac{4}1$

$n = 150$

Hence, there are 150 small equilateral triangles in the regular hexagon