The first one is incorrect. The actual solution of the problem is 5/2. I’m sorry i’m in a rush right now. But that’s all I can answer right now.
9514 1404 393
Answer:
Step-by-step explanation:
Let a and s represent the prices of adult and student tickets, respectively.
13a +12s = 211 . . . . . . ticket sales the first day
5a +3s = 65 . . . . . . . ticket sales the second day
Subtracting the first equation from 4 times the second gives ...
4(5a +3s) -(13a +12s) = 4(65) -(211)
7a = 49 . . . . . . . simplify
a = 7 . . . . . . . divide by 7
5(7) +3s = 65 . . . . substitute into the second equation
3s = 30 . . . . . . . subtract 35
s = 10 . . . . . . . divide by 3
The price of one adult ticket is $7; the price of one student ticket is $10.
Answer:
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Step-by-step explanation:SDK
s
d
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d
Sq of 196 is 14 then x2 = 28 then 25= 5
The price of the new stock would $5.25 because you have to add the $4.75 and $0.50 to find the new price
