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GalinKa [24]
3 years ago
14

Evaluate the determinant for the following matrix: [- 5 1 1 4] A. –21 B. 19 C. –17 D. –24

Mathematics
2 answers:
mariarad [96]3 years ago
6 0

Answer:

-21

Step-by-step explanation:

I assume this is a 2 by 2 matrix.

\begin{bmatrix} -5 & 1\\1 & 4 \end{bmatrix}

determinant = -5 * 4  - 1 * 1 = -20 - 1 = -21

lara [203]3 years ago
6 0

Answer:

Option A.

Step-by-step explanation:

If a matrix is defined as

A=\begin{bmatrix}a\:&\:b\:\\ c\:&\:d\:\end{bmatrix}\:

then its determinant is

|A|=\:ad-bc

Let the given matrix is

B=\begin{bmatrix}-5&1\\ \:1&4\end{bmatrix}

We need to find the determinant for the given matrix.

Using the above formula we get

|B|=\left(-5\right)\cdot \:4-1\cdot \:1

|B|=-21

The determinant of given matrix is -21. Therefore, the correct option is A.

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Step-by-step explanation:

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3 years ago
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Kisachek [45]
-2 < n \leq 3

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Mark as brainliest if this helped! :)
5 0
3 years ago
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Solnce55 [7]

Answer:

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Step-by-step explanation:

7 0
3 years ago
Can someone help me with these Algebra 1 questions, they are pretty tough and i need help since i don't fully understand it yet.
Hatshy [7]
I will answer second attachment and after since I can't see the firs attachment



2nd attachment

if x is negative, then the first number gets infinitely small
look at the second number, the first 2 is -2 which is wrong since it should be +2
3rd option is not because if x=-2, then y=1
answer is D


3rd attachment
2nd: f(x)=60*1.15^x
3rd: no xint
6th: after 7.86 years value tripples
7th maybe: after 8 years value is 183.51, not exatly 184.00


4th attachment
nth score is
f(n)=57+4(n-1)
9th is
f(9)=57+4(9-1)
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5th
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4 0
2 years ago
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