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Eduardwww [97]
3 years ago
10

Is (0, 8) a solution of 4x – y = 8? yes no cannot be determined

Mathematics
1 answer:
jolli1 [7]3 years ago
3 0
No, (0-8) is the first point plotted on the graph but not (0,8).
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Tickets to a baseball game cost $18.95, $12.95, or $9.95. A hot dog and soda combo costs $5.50. The Madison family is having a r
I am Lyosha [343]
Hmmm Interesting: 189.5+129.5+99.5+53
I got 471.5 Dollars....

Because Look If they buy 10 tickets each category it be 18.95 times 10= 189.5
then 12.95 times= 129.5 , Then 9.95 times= 99.5.... Also if they plan to get 30 combos it be also 5.50 times 30,,, You add the answers and it will give you 471.5 dollars. You can try doing it in a caculator (:
3 0
3 years ago
Read 2 more answers
If f(x)=3x+7, find: f(-2)= [?]
miv72 [106K]

Answer:

1

Step-by-step explanation:

substitute -2 for x

3(-2) + 7

-6 + 7

1

hope it helps :)

mark brainliest!!

6 0
3 years ago
kai calculates that he spends 15% of a school day in science class. If he spends 75 minutes in science class, how many minutes d
jasenka [17]
Im not sure but I would think you would divide 75 by .15. That would get you 500. So 500 minutes would be your answer.
5 0
3 years ago
Rewrite this number in appropriate scientific notation of 4,770,000
Cerrena [4.2K]
The number 4,770,000 in appropriate scientific notation would be 4.770000x10^16

3 0
3 years ago
Mr. Acosta, a sociologist, is doing a study to see if there is a relationship between the age of a young adult (18 to 35 years o
Alik [6]

Answer:

There is a relationship between the age of a young adult and the type of movie preferred.

Step-by-step explanation:

In this case we need to test whether there is a significance relationship between the age of a young adult and the type of movie preferred.

The hypothesis can be defined as:

<em>H₀</em>: Age of a young adult and movie preference are independent.

<em>Hₐ</em>: Age of a young adult and movie preference are not independent.

The test statistic is given as follows:

\chi^{2}=\sum\limits^{n}_{i=1}{\frac{(O_{i}-E_{i})^{2}}{E_{i}}}

Consider the table below.

The formula to compute the expected frequencies is:

E_{i}=\frac{\text{Row Total}\times \text{Column Total}}{\text{Total}}

The Chi-square test statistic value is:

\chi^{2}=\sum\limits^{n}_{i=1}{\frac{(O_{i}-E_{i})^{2}}{E_{i}}}=2.6013

The significance level of the test is, <em>α</em> = 0.05.

The degrees of freedom of the test is,

df = (r - 1)(c - 1)

   = (3 - 1)(3 - 1)

   = 2 × 2

   = 4

Compute the <em>p</em>-value as follows:

<em>p</em>-value = 0.6266

*Use a Chi square table.

As the <em>p-</em>value is more than the significance level the null hypothesis was failed to be rejected.

Thus, concluding that there is a relationship between the age of a young adult (18 to 35 years old) and the type of movie preferred.

5 0
3 years ago
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