Question

Find the Sin A, Cos A, and Tan A. (Write your answer as simplified ratios.)

Answer 1

Answer:

see explanation

Step-by-step explanation:

sinA = $\frac{opposite}{hypotenuse}$ = $\frac{BC}{AB}$, thus

sinA = $\frac{2\sqrt{19} }{20}$ = $\frac{\sqrt{19} }{10}$

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cosA = $\frac{adjacent}{hypotenuse}$ = $\frac{AC}{AB}$, thus

cosA = $\frac{18}{20}$ = $\frac{9}{10}$

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tanA = $\frac{opposite}{adjacent}$ = $\frac{BC}{AC}$, thus

tanA = $\frac{2\sqrt{19} }{18}$ = $\frac{\sqrt{19} }{9}$