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3 years ago

Answer the questions when examining the data.

Mathematics

1 answer:

loris [4]3 years ago

8 0

<em>Greetings from Brasil...</em>

In this case, we can say:

Domain = [0; 6]

Image = [3; 192]

<em>see attachment</em>

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Write as a fraction in the simplest from 80%

Georgia [21]

Answer:

4/5

Step-by-step explanation:

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3 years ago

What is 33 photos into two grours so the ratio is 4 to 7

Keith_Richards [23]

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3 years ago

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Y=-2(x-3)^2 +10<br> Y=4x

shepuryov [24]

Answer:

i might be wrong but 8 if not (2,8) if not sorry

Step-by-step explanation:

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3 years ago

(5,2) (8,2), (8,5) and (?,?)

Luba_88 [7]

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3 years ago

What are the possible rational roots of the polynomial equation?<br><br> 0=2x7+3x5−9x2+6

RoseWind [281]

Answer: $\pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}$

Step-by-step explanation:

We can use the Rational Root Test.

Given a polynomial in the form:

$a_nx^n +a_{n- 1}x^{n - 1} + … + a_1x^1 + a_0 = 0$

Where:

- The coefficients are integers.

- $a_n$ is the leading coeffcient ( $a_n\neq 0$ )

- $a_0$ is the constant term $a_0\neq 0$

Every rational root of the polynomial is in the form:

$\frac{p}{q}=\frac{\pm(factors\ of\ a_0)}{\pm(factors\ of\ a_n)}$

For the case of the given polynomial:

$2x^7+3x^5-9x^2+6=0$

We can observe that:

- Its constant term is 6, with factors 1, 2 and 3.

- Its leading coefficient is 2, with factors 1 and 2.

Then, by Rational Roots Test we get the possible rational roots of this polynomial:

$\frac{p}{q}=\frac{\pm(1,2,3,6)}{\pm(1,2)}=\pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}$

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3 years ago