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KonstantinChe [14]
3 years ago
15

3/8

ac{3}{8} (x - 1)(x - 9)" alt=" \frac{3}{8} (x - 1)(x - 9)" align="absmiddle" class="latex-formula">
(x-1)(x-9)
Mathematics
1 answer:
Verdich [7]3 years ago
8 0
The first step for solving this expression is to distribute \frac{3}{8} through the first set of parenthesis.
( \frac{3}{8}x -  \frac{3}{8}) × (x - 9)
Now use the FOIL method to multiply each term in the first parenthesis by each term in the second parenthesis. This will look like the following:
\frac{3}{8}x × x - \frac{3}{8}x × 9 - \frac{3}{8}x - \frac{3}{8} × (-9)
Remember that multiplying two negatives together equals a positive,, so the expression changes to:
\frac{3}{8}x × x - \frac{3}{8}x × 9 - \frac{3}{8}x + \frac{3}{8} × 9
Calculate the product of all of the sets of multiplication to make the expression become:
\frac{3}{8}x² - \frac{27}{8}x - \frac{3}{8}x + \frac{27}{8}
Lastly,, calculate the difference of - \frac{27}{8}x - \frac{3}{8}x to find your final answer.
\frac{3}{8}x² - \frac{15}{4}x + \frac{27}{8}
Let me know if you have any further questions.
:)
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Does this table represent an exponential function? x 1 2 3 4 y 4 16 64 256
4vir4ik [10]

Answer:

Yes, the given table represent an exponential function.

Step-by-step explanation:

Given table is :

x y

1 4

2 16

3 64

4 256

Now we need to identify if the given table represent an exponential function or not. To find that we need to check if we can write the numbers in y-column in form of exponential function y=ab^x.

We see that y-values are basically powers of 4 so we can write the related function as y=4^x.

Which is clearly in form of y=ab^x.

Hence yes, the given table represent an exponential function.

6 0
3 years ago
Solve using the quadratic formula 3x^2+11x+5=0
storchak [24]

Answer:

3x^2 + 11x + 5 = 0 : x = \frac{-11 + \sqrt{61} }{6} , x = \frac{-11 - \sqrt{61} }{6}

Decimal:

(x = -0.53162..., x = -3.13504...)

Step-by-step explanation:

3x^2+11x+5=0

Solve with the quadratic formula:

For a quadratic equation of the form ax^2+bx+c=0 the solutions are:

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

For a=3,\:b=11,\:c=5:\quad x_{1,\:2}=\frac{-11\pm \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3}

x=\frac{-11 + \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3} : \frac{-11 + \sqrt{61} }{6}

x=\frac{-11 - \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3} : \frac{-11 - \sqrt{61} }{6}

The solutions to the quadratic equation are:

x=\frac{-11+\sqrt{61}}{6},\:x=\frac{-11-\sqrt{61}}{6}

Hope I helped. If so, may I get brainliest and a thanks?

Thank you, have a good day! =)

8 0
3 years ago
HELP ASAP. Teacher didnt teach us this.
mina [271]

Answer:

A = 624

B = 14.76 or 14.8 or 15inches

Standard form in polynomial for Area = 26 x 24 = .624in^2.....

2(5 + 8) x 2( 5 + 7)

26 x 24 = 624 in^2

This is because the rectangle width indifference is 1/10th of the length measuring 2inches more, then we see both sides of the frame are equal to 2inches and match this measure for x = 2inches both width and length. We add 4 to each side 22 x 20 + 4x^2 we separate 4x^2 into 4x both sides, this has become 26 x 24 = 624in^2

as 4 was added each side.

Question 2.  

We find the width is shown left to right in rectangles, they are the sides.

So Area 4 x 24 = 96in^2

or 6.5 of the 24 = 24/6.5 = 3.69 inches

26 /6.5 = scale of 6.5: 26 = 4 inches

Therefore Area = 3.69 x 4 = 14.76

if it was square frame it would be 16inches

Go for 14.76in^2 as ithe question says 4 inches and it becomes, a replaced width only and it must be still to scale as shown above with 24/6.5 = 3.69  so 3,69 x 4 = 14.76. Last resort would be that the length as kept at 24 x 4 = 96 and in this response it does exactly what the question asks the width changes only.

5 0
3 years ago
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