1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
KonstantinChe [14]
3 years ago
15

3/8

ac{3}{8} (x - 1)(x - 9)" alt=" \frac{3}{8} (x - 1)(x - 9)" align="absmiddle" class="latex-formula">
(x-1)(x-9)
Mathematics
1 answer:
Verdich [7]3 years ago
8 0
The first step for solving this expression is to distribute \frac{3}{8} through the first set of parenthesis.
( \frac{3}{8}x -  \frac{3}{8}) × (x - 9)
Now use the FOIL method to multiply each term in the first parenthesis by each term in the second parenthesis. This will look like the following:
\frac{3}{8}x × x - \frac{3}{8}x × 9 - \frac{3}{8}x - \frac{3}{8} × (-9)
Remember that multiplying two negatives together equals a positive,, so the expression changes to:
\frac{3}{8}x × x - \frac{3}{8}x × 9 - \frac{3}{8}x + \frac{3}{8} × 9
Calculate the product of all of the sets of multiplication to make the expression become:
\frac{3}{8}x² - \frac{27}{8}x - \frac{3}{8}x + \frac{27}{8}
Lastly,, calculate the difference of - \frac{27}{8}x - \frac{3}{8}x to find your final answer.
\frac{3}{8}x² - \frac{15}{4}x + \frac{27}{8}
Let me know if you have any further questions.
:)
You might be interested in
Show that a sequence {sn} coverages to a limit L if and only if the sequence {sn-L} coverages to zero.
Andreyy89

Let {s_n}_{n\in\Bbb N} be a sequence that converges to L. This means for any \varepsilon>0, there is some N such that |s_n-L| for all n>N. From this inequality we see that |(s_n-L)-0|, so it follows that s_n-L\to0.

On the other hand, let {s_n-L} be a sequence that converges to 0. This means |(s_n-L)-0| for all large enough n, and we get the simpler inequality for free, |s_n-L|, so it follows that s_n\to L.

3 0
3 years ago
A proportional relationship between the number of pounds of potatoes (x) and the price in dollars (y) is graphed, and the ordere
olga55 [171]

Answer:

Part A: The price of 1 pound of potatoes is 1 dollar and 25 cents (1.25) because 5 / 4 is 1.25 and that's 1 pound

Part B: The ordered pair (10, 8) represents that 10 punds of potatoes cost 8 dollars

4 0
2 years ago
Which two grids have 25% shaded
Licemer1 [7]
We can’t see the grids
5 0
3 years ago
Read 2 more answers
Please help me online school isnt fit for me lol
worty [1.4K]

Answer:

The answer is A!!

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Plz help me plz help me
Nutka1998 [239]

Answer:

A. W

Step-by-step explanation:

Because this is a rigid transformation, quadrilaterals WXYZ and ABCD are congruent. Corresponding parts of corresponding figures are congruent, so W is congruent to A and because we know the measure of angle A, you also know the angle measure of W.

8 0
3 years ago
Other questions:
  • 3.48 An apartment seeker in Manhattan estimates that 10% of the available apartments in her price range are in acceptable condit
    12·1 answer
  • What is the missing statement in the proof?
    7·2 answers
  • Determine the equation of g(x) that results from translating the function f(x)=x^2+9 upward 10 units.
    5·2 answers
  • Please help me I'm desperate!! Debbie is making bows that use 1/5 yard of ribbon each. If Debbie has 3 yards of ribbon how many
    13·1 answer
  • Can someone hep me with this
    7·2 answers
  • Calculate the area of triangle WXY with altitude YZ, given W(2, −1), X(6, 3), Y(7, 0), and Z(5, 2). (6 points) 8 square units 9.
    5·2 answers
  • What Is The Probability That A Visitor Adopts A Dog And A Cat? None Dog Total None 35 45 80 Cat 70 150 220 Total 105 195 300.
    8·1 answer
  • Help asap! Identify the function shown in this graph.
    5·1 answer
  • Please give answer for this
    9·1 answer
  • Find the sum..<br><br> 7/4 − (−1/2)<br><br><br> Please Help! I need it now!
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!