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postnew [5]
4 years ago
5

2 Producto o servicio que haya experimentado una innovación técnica

Computers and Technology
1 answer:
Artemon [7]4 years ago
4 0

Answer:

El producto o servicio también puede atraer a un mercado más grande y corriente si  La innovación disruptiva es una teoría que se refiere a un concepto, producto o

Explanation:

Esperemos que esto le ayude

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8 1
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To adjust the height or width to fit the dialog within it, you should use these options. Click all that apply
Blizzard [7]

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Explanation:

I took the test.

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What is the text that is entered into a cell used to identify the purpose of the worksheet, columns, and rows?
castortr0y [4]
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Date and Time: -  Haven't found anything on this one



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7 0
4 years ago
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Which of these strategies do you practice when tests are returned to you? Check all that apply.
victus00 [196]

Answer:

I apply numbers...

5, 6 and 3

7 0
2 years ago
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Given a pattern as the first argument and a string of blobs split by | show the number of times the pattern is present in each b
Ierofanga [76]

Answer:

The code is below

Explanation:

import java.io.BufferedReader;

import java.io.IOException;

import java.io.InputStreamReader;

import java.nio.charset.StandardCharsets;

public class Main {

  /**

  *

  * Iterate through each line of input.

  *

  */

  public static void main(String[] args) throws IOException {

      InputStreamReader reader = new InputStreamReader(System.in, StandardCharsets.UTF_8);

      BufferedReader in = new BufferedReader(reader);

      String line;

      while ((line = in.readLine()) != null) {

          String[] splittedInput = line.split(";");

          String pattern = splittedInput[0];

          String blobs = splittedInput[1];

          Main.doSomething(pattern, blobs);

      }

  }

  public static void doSomething(String pattern, String blobs) {

      // Write your code here. Feel free to create more methods and/or classes

      int sum = 0;

      String arrblobs[] = blobs.split("\\|");

      for (int i = 0; i < arrblobs.length; ++i) {

          int answer = 0, index = 0;

          for (;;) {

              int position = arrblobs[i].indexOf(pattern, index);

              if (position < 0)

                  break;

              answer++;

              index = position + 1;

          }

          System.out.print(answer + "|");

         

          sum = sum + answer;

      }

      System.out.println(sum);

  }

}

5 0
3 years ago
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